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我想从数据库中动态显示菜单。但是我的菜单项正在显示,但是当我以前单击菜单时,子菜单没有显示。请告诉我错误在哪里

我的代码是

protected void Page_Load(object sender, EventArgs e)
{
    if(!IsPostBack)
    { GetMenuData(); }
}
private void GetMenuData()
{
    DataTable table = new DataTable();
    SqlConnection conn = new SqlConnection(@"Data Source=ST015\SQLEXPRESS;Initial Catalog=MyData;Integrated Security=True");
    string sql = "select menuId,Menuname,MenuDescription,ParentMenuid,MenuUrl from Categories";
    SqlCommand cmd = new SqlCommand(sql, conn);
    SqlDataAdapter da = new SqlDataAdapter(cmd);
    da.Fill(table);
    DataView view = new DataView(table);
    view.RowFilter = "ParentMenuId is NULL";
    foreach (DataRowView row in view)
    {
        MenuItem menuItem = new MenuItem(row["MenuName"].ToString(),
            row["MenuId"].ToString());
        menuItem.NavigateUrl = row["MenuUrl"].ToString();
        Menu1.Items.Add(menuItem);
        AddChildItems(table, menuItem);
    }
}
private void AddChildItems(DataTable table, MenuItem menuItem)
{
    DataView viewItem = new DataView(table);
    viewItem.RowFilter = "ParentMenuId=" + menuItem.Value;
    foreach (DataRowView childView in viewItem)
    {
        MenuItem childItem = new MenuItem(childView["MenuName"].ToString(),
            childView["MenuId"].ToString());
        childItem.NavigateUrl = childView["MenuUrl"].ToString();
        menuItem.ChildItems.Add(childItem);
        AddChildItems(table, childItem);
    }
}
4

3 回答 3

1

我认为当您单击菜单项时,它会导致页面出现,PostBack 并且您在第一次加载页面时正在创建菜单。因此您无法在单击菜单项时看到菜单。只需调用GetMenuData();页面加载方法而不检查IsPostBack属性。

protected void Page_Load(object sender, EventArgs e)
{
   GetMenuData(); 
}
于 2012-10-25T10:49:00.933 回答
1

为菜单创建一个表

CREATE TABLE [dbo].[tblMenuMaster](
[MenuID] [int] IDENTITY(1,1) NOT NULL,
[MenuName] [varchar](100) NULL,
[DisplayOrder] [int] NULL,
PRIMARY KEY CLUSTERED 
(
[MenuID] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

为子菜单创建另一个表

CREATE TABLE [dbo].[tblSubMenuMaster](
[SubMenuID] [int] IDENTITY(1,1) NOT NULL,
[MenuID] [int] NULL,
[SubMenuName] [varchar](100) NULL,
[MainMenuDisplayOrder] [int] NULL,
[DisplayOrder] [int] NULL,
[SubMenuUrl] [varchar](500) NULL,
[VisibleInMenu] [bit] NULL,
PRIMARY KEY CLUSTERED 
(
[SubMenuID] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

现在转到母版页.. HTML 代码是:

   <div class="menubar">
        <%--<ul class="tabs">--%>
        <asp:Literal ID="ltMenus" runat="server"></asp:Literal>
        <%--</ul>--%>
    </div>

代码背后的代码是:

private void GenerateMenus()
{
    clsMenu obj = new clsMenu();
    System.Data.DataSet ds = new System.Data.DataSet();
    String PageName = "";
    PageName = Path.GetFileName(Page.AppRelativeVirtualPath);
    ds = obj.GetMenusByRole(GetRoleId(), PageName);

    StringBuilder sb = new StringBuilder("<ul class='tabs'>");

    foreach (System.Data.DataRow row in ds.Tables[0].Rows)
    {
        sb.Append(String.Format("<li class='{0}'><a rel='{1}' href='{1}' > {2} </a> ", Convert.ToString(row["css"]), ResolveUrl(Convert.ToString(row["PagePath"])), Convert.ToString(row["MenuName"])));
        //sb.Append(String.Format("<li '><a rel='{0}' href='{0}' > {1} </a> ", ResolveUrl(Convert.ToString(row["PagePath"])), Convert.ToString(row["MenuName"])));

        System.Data.DataTable t = CCMMUtility.GetFilterDataforIntColumn("MenuID", Convert.ToString(row["MenuID"]), ds.Tables[1]);
        if (t.Rows.Count > 0)
        {
            sb.Append("<ul>");

            for (int i = 0; i < t.Rows.Count; i++)
            {
                sb.Append(String.Format("<li><a href='{0}' class='dir' style='cursor: pointer;'>{1}</a></li>", ResolveUrl(Convert.ToString(t.Rows[i]["PagePath"])), Convert.ToString(t.Rows[i]["PageAliasName"])));
            }

            sb.Append("</ul>");
        }
        sb.Append("</li>");
    }

    sb.Append("</ul>");


    ltMenus.Text = sb.ToString();

}

它需要存储过程来根据角色 ID 调用菜单的动态,如下所示

CREATE PROCEDURE [dbo].[proc_GetMenusByRole]
(
@RoleId int,  
@PageName varchar(100)
)
AS
SET NOCOUNT ON;
SELECT mm.MenuID, mm.MenuName,dbo.Extract_CssNameForMenuByMenuIDAndPageName(mm.MenuID, @PageName) as css
,dbo.proc_Extract_MenuPageByRoleIDAndMenuID(@RoleId, mm.MenuID)
as PagePath , mm.DisplayOrder   FROM tblMenuMaster mm WHERE mm.MenuID IN (SELECT s.MenuID from tblSiteRolePermissions p INNER JOIN
tblSitePages s ON p.fkSitePageId = s.pkSitePageId
WHERE (p.fkRoleId = @RoleId and p.ViewOnly=1))   
Union All   
select 0 as menuid ,'Change Password' as MenuName,  
case @pagename   
when 'ChangePassword.aspx' then 'active'  
else ''  
end  as css,'~/User/ChangePassword.aspx' as PagePath, 10000 as Displayorder  
ORDER BY DisplayOrder     
SELECT s.MenuID, s.pkSitePageId, s.PageAliasName, s.SitePageName,s.pagepath from tblSiteRolePermissions p 
INNER JOIN tblSitePages s ON p.fkSitePageId = s.pkSitePageId  WHERE (p.fkRoleId =@RoleId and p.ViewOnly=1) ORDER BY s.pkSitePageId  

//新的sp从这里开始

CREATE function [dbo].[Extract_CssNameForMenuByMenuIDAndPageName](@MenuID int, 
PageName varchar(100))
returns nvarchar(50)
as begin      
declare @result nvarchar(50) 
set @result = ''    
IF EXISTS (SELECT pkSitePageId FROM tblsitepages WHERE (MenuID = @MenuID) AND (UPPER(SitePageName) = @PageName)) 
 BEGIN    
  SET @result = 'active'    
 END    
return @result    
end  

// 另一个使用的 sp 是

CREATE function [dbo].[proc_Extract_MenuPageByRoleIDAndMenuID]
(@RoleId int, @MenuID int)
returns nvarchar(500) 
as begin          
declare @result nvarchar(500)
SELECT top 1 @result = s.pagepath FROM tblSitePages AS s INNER JOIN tblSiteRolePermissions AS p ON s.pkSitePageId = p.fkSitePageId
WHERE (p.fkRoleId = @RoleId) AND (s.MenuID = @MenuID)  and p.ViewOnly=1
ORDER BY s.pkSitePageId 
return  @result
end  

它只是一种方法,您可以根据您的要求对其进行修改............

proc_Extract_MenuPageByRoleIDAndMenuID sp 用于获取页面名称及其路径,

Extract_CssNameForMenuByMenuIDAndPageName sp 用于将活动类设置为第一个li表示第一个菜单。跳这会帮助你.....它的工作代码..

于 2012-10-25T10:54:00.407 回答
0

您的代码中没有错误它运行良好可能您添加到菜单的数据中存在错误。可能是“ParentMenuid”丢失或可能是错误的

于 2012-10-25T10:45:36.537 回答