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您好需要一些关于使用街景的想法/建议，我正在获取使用地点 Api 按类型执行搜索的地点详细信息，下面是我的搜索地点代码

function SearchData(type){

    $('#placedata').empty();
        var myLatlng = new google.maps.LatLng(parseFloat(searchLatitute), parseFloat(searchLongitute));
        map = new google.maps.Map(document.getElementById('map_canvas'), {
                    mapTypeId: google.maps.MapTypeId.ROADMAP,
                    center: myLatlng,
                    zoom: 10});
        var request = {location: myLatlng,rankBy: google.maps.places.RankBy.DISTANCE,types: [type]};
        var service = new google.maps.places.PlacesService(map);
        service.search(request, callback);
  }

  function callback(results, status,pagination) {
    if (status == google.maps.places.PlacesServiceStatus.OK) {
    for (var i = 0; i < results.length; i++) {
        var place = results[i];
        createMarker(place);

  function createMarker(place) {
        var placeLoc = place.geometry.location;
        var marker = new google.maps.Marker({map: map,zIndex: 100,position: place.geometry.location});

    var request = {reference: place.reference};
    service = new google.maps.places.PlacesService(map);
    service.getDetails(request, function(details, status) {//alert("address  "+details.formatted_address);
    if (status == google.maps.places.PlacesServiceStatus.OK) {
        $('#placedata').append('<tr><td><a href='+details.url+'>'+details.name+'</a></td></tr>');

    }
});

我在我的网页中显示结果..我想要实现的是为每个地址添加街景。任何建议，将不胜感激。

4

1 回答 1

1

您有 2 个选项：

  1. 只需使用Static StreetView-Image-API提供的图像。但是如果这个地方没有可用的图像，你会得到一个错误图像。
  2. 使用getPanoramaByLocation()请求给定位置的 StreetView 详细信息，当此地点没有可用图像时，您可以处理这种情况，但需要进一步请求，并且您还可以加载全景图。

<edit>

根据要求，案例 #2 可以这样处理（以下代码替代您当前的 service.getDetails()-callback）：

function(details, status) {
    if (status == google.maps.places.PlacesServiceStatus.OK) {

      //create streetViewService-object once
      if(!window.streetViewService)window.streetViewService 
        = new google.maps.StreetViewService;   


        (function(d){
          //append the tr to the table, note the additional td and div
          //thats where the panorama will be placed later
          var target=$('<tr><td><a href='+
                        d.url+'>'+d.name+
                       '</a></td><td><div/></td></tr>');

          target.appendTo('#placedata');

          //get the panorama
          window.streetViewService
            .getPanoramaByLocation(d.geometry.location,
                                   50,
                                   function(r,status){
                                   //check if there was an result
                                   if(status==google.maps.StreetViewStatus.OK){
                                    //create the panorama
                                    new google.maps
                                      .StreetViewPanorama(
                                          $('td:last div:last',target)
                                            .css({width:200,height:200})[0],
                                         {pano:r.location.pano});
                                  }
                                  else{
                                    $('td:last div:last',target)
                                     .text('no panorama available');
                                  }
                                });
        })(details)


    }
}
于 2012-10-25T11:15:55.117 回答