2

在字符串中搜索给定模式并在不使用 awk 的情况下回显它的最佳方法是什么（在 bash 中）？我想使用标准命令，如grep, cat, cut, 或sed.

例子：

我想从lspci命令的输出中去掉所有 USB 控制器的设备地址：

[artlab@localhost ~]$ lspci

00:00.0 Host bridge: Intel Corporation Core Processor DRAM Controller (rev 18)
00:1a.0 USB controller: Intel Corporation 5 Series/3400 Series Chipset USB2 Enhanced Host Controller (rev 05)
00:1c.0 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 1 (rev 05)
00:1c.4 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 5 (rev 05)
00:1c.5 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 6 (rev 05)
00:1d.0 USB controller: Intel Corporation 5 Series/3400 Series Chipset USB2 Enhanced Host Controller (rev 05)
00:1e.0 PCI bridge: Intel Corporation 82801 PCI Bridge (rev a5)
00:1f.0 ISA bridge: Intel Corporation 3400 Series Chipset LPC Interface Controller (rev 05)
00:1f.2 RAID bus controller: Intel Corporation 82801 SATA Controller [RAID mode] (rev 05)
00:1f.3 SMBus: Intel Corporation 5 Series/3400 Series Chipset SMBus Controller (rev 05)
02:00.0 Ethernet controller: Intel Corporation 82574L Gigabit Network Connection
03:00.0 Ethernet controller: Intel Corporation 82574L Gigabit Network Connection
04:03.0 VGA compatible controller: Matrox Graphics, Inc. MGA G200eW WPCM450 (rev 0a)

我想检索（打印）这两个字符串：

00:1a.0
00:1d.0
4

3 回答 3

3

我不知道谁会想出更多的可能性。

lspci | grep 'USB Controller' | sed "s/ .*//"
lspci | grep 'USB Controller' | grep -o '^[^ ]*'
lspci | grep 'USB Controller' | while read id rest ; do echo $id ; done
lspci | grep 'USB Controller' | cut -f 1 -d ' '
于 2012-10-25T08:08:17.670 回答
1 
sed -n '/USB controller/{s/ .*//;p}'
于 2012-10-25T08:09:35.697 回答
1 
lspci | grep 'USB Controller' | cut -d' ' -f1
于 2012-10-25T08:10:19.213 回答