我有一个使用某种协议将数据写入串行端口的功能。当函数写入一帧时,它等待接收者的一个答复。如果没有收到应答,它必须在 3 次超时期间重新发送数据,并且在 3 次超时结束时没有成功,关闭通信...
我有这个功能:
int serial_write(int fd, unsigned char* send, size_t send_size) {
......
int received_counter = 0;
while (!RECEIVED) {
Timeout.tv_usec = 0; // milliseconds
Timeout.tv_sec = timeout; // seconds
FD_SET(fd, &readfs);
//set testing for source 1
res = select(fd + 1, &readfs, NULL, NULL, &Timeout);
//timeout occurred.
if (received_counter == 3) {
printf(
"Connection maybe turned off! Number of resends exceeded!\n");
exit(-1);
}
if (res == 0) {
printf("Timeout occured\n");
write(fd, (&I[0]), I.size());
numTimeOuts++;
received_counter++;
} else {
RECEIVED = true;
break;
}
}
......
}
我已验证此函数在超时时不会重新发送数据。为什么?