1

我使用 AsyncTask 从 URL 下载文件。该文件已保存,我可以在我的 SD 卡上看到它。在我的应用程序中,我想在下载后打开此文件,但出现以下错误:

java.io.FileNotFoundException: /mnt/sdcard/XML/zurt.xml: open failed: ENOENT (No such file or directory)

我必须在下载和打开文件之间等待指定的时间吗?问题是什么?

我有这两个权限:

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" >
</uses-permission>
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" >
</uses-permission>

我的异步任务:

/**
     * Download XML from URL async
     */
    // usually, subclasses of AsyncTask are declared inside the activity class.
    // that way, you can easily modify the UI thread from here
    private class DownloadFile extends AsyncTask<String, Integer, String> {
     @Override
     protected String doInBackground(String... sUrl) {
         try {
             URL url = new URL(sUrl[0]);
             URLConnection connection = url.openConnection();
             connection.connect();
             // this will be useful so that you can show a typical 0-100% progress bar
             int fileLength = connection.getContentLength();

             // create a File object for the parent directory
             File xmlDirectory = new File(Environment.getExternalStorageDirectory()+ FileSeperator+"XML"
                     +FileSeperator);
             // have the object build the directory structure, if needed.
             xmlDirectory.mkdirs();

             // create a File object for the output file
             File outputFile = new File(xmlDirectory, Name+FileExtension);
             // download the file
             InputStream input = new BufferedInputStream(url.openStream());
             OutputStream output = new FileOutputStream(outputFile);

             byte data[] = new byte[1024];
             long total = 0;
             int count;
             while ((count = input.read(data)) != -1) {
                 total += count;
                 // publishing the progress....
                 publishProgress((int) (total * 100 / fileLength));
                 output.write(data, 0, count);
             }

             output.flush();
             output.close();
             input.close();
         } catch (Exception e) {
             System.out.println(e);
         }
         return null;
     }
     @Override
     protected void onPreExecute() {
         super.onPreExecute();
         mProgressDialog.show();
     }

    protected void onPostExecute() {
         mProgressDialog.dismiss();
     }

     @Override
     protected void onProgressUpdate(Integer... progress) {
         super.onProgressUpdate(progress);
         mProgressDialog.setProgress(progress[0]);
     }
 }

此代码尝试打开保存的文件:

/**
 * XML Parser
 * */
private ArrayList<Datapoint> parseXML() {

try {           
    Log.w("AndroidParseXMLActivity", "Start");
    /** Handling XML */
    SAXParserFactory spf = SAXParserFactory.newInstance();
    SAXParser sp = spf.newSAXParser();
    XMLReader xr = sp.getXMLReader();

    File file = new File(Environment.getExternalStorageDirectory()+ FileSeperator+"XML"
    +FileSeperator+ Name + FileExtension);

    XMLContentHandler myXMLHandler = new XMLContentHandler();
    xr.setContentHandler(myXMLHandler);

        xr.parse(new InputSource(new InputStreamReader(new FileInputStream(file)))); 

    itemsList = myXMLHandler.getItemsList();

    Log.w("AndroidParseXMLActivity", "Done");
}
catch (Exception e) {
    Log.w("AndroidParseXMLActivity",e );
}
return itemsList ;

}

4

1 回答 1

3

我更改了以下行并且它有效:

protected void onPostExecute() {
         parseXML();
         mProgressDialog.dismiss();
     }
于 2012-10-29T07:40:43.630 回答