sql - 使用 MAX 和 GROUP BY 选择所有对应的字段

Question

我有这张桌子：

我想提出一个请求，该请求将为每个deal_id具有最高的行timestamp和相应的status_id.

所以对于这个例子，我会返回 2 行：

1226, 3, 2009-08-18 12:10:25
1227, 2, 2009-08-17 14:31:25

我试着用这个查询来做

SELECT deal_id, status_id, max(timestamp) FROM deal_status GROUP BY deal_id

但它会返回错误status_id：

1226, 1, 2009-08-18 12:10:25
1227, 1, 2009-08-17 14:31:25

Answer 1

没有一个主键字段，我认为你最好的选择是：

select * from deal_status
inner join
  (select deal_id as did, max(timestamp) as ts
  from deal_status group by deal_id) as ds
  on deal_status.deal_id = ds.did and deal_status.timestamp = ds.ts

如果您允许同一产品同时具有两种不同的状态，这仍然不起作用

Answer 2

嗨，我希望这能给你想要的

select deal_id,status_id, timestamp from deal_status 
inner join
  (select deal_id as did,max(timestamp) as ts
  from deal_status group by deal_id  )as ds
  on deal_status.deal_id = ds.did and deal_status.timestamp = ds.ts order by deal_id