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我需要在服务器上上传文件（具有不同的扩展名，即 .txt、.jpg、.pdf ......）。我创建了一个接受 http 请求的站点，并将虚拟目录映射到物理目录。所有这些在下载中都可以正常工作，现在我必须实现上传。

这是我的代码

private void UploadFile(string uploadFileName, string localFileName)
    {
        //long length = 0;
        string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x");
        HttpWebRequest httpWebRequest2 = (HttpWebRequest)WebRequest.Create(uploadFileName);
        httpWebRequest2.ContentType = "multipart/form-data; boundary=" + boundary;
        httpWebRequest2.Method = "POST";
        httpWebRequest2.KeepAlive = true;
        httpWebRequest2.Credentials = new NetworkCredential("USER", "PASSWORD", "DOMAIN"); 

        Stream memStream = new System.IO.MemoryStream();

        byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" +boundary + "\r\n");

        string formdataTemplate = "\r\n--" + boundary +"\r\nContent-Disposition: form-data; name=\"{0}\";\r\n\r\n{1}";

        memStream.Write(boundarybytes, 0, boundarybytes.Length);

        string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\n Content-Type: application/octet-stream\r\n\r\n";

        string header = string.Format(headerTemplate, "uplTheFile", localFileName);

        byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);

        memStream.Write(headerbytes, 0, headerbytes.Length);

        FileStream fileStream = new FileStream(localFileName, FileMode.Open, FileAccess.Read);
        byte[] buffer = new byte[1024];

        int bytesRead = 0;

        while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
        {
            memStream.Write(buffer, 0, bytesRead);
        }

        memStream.Write(boundarybytes, 0, boundarybytes.Length);

        fileStream.Close();

        httpWebRequest2.ContentLength = memStream.Length;

        Stream requestStream = httpWebRequest2.GetRequestStream();
        //error returned in lenght field: "This stream does not support seek operations."

        memStream.Position = 0;
        byte[] tempBuffer = new byte[memStream.Length];
        memStream.Read(tempBuffer, 0, tempBuffer.Length);
        memStream.Close();
        requestStream.Write(tempBuffer, 0, tempBuffer.Length);
        requestStream.Close();

        WebResponse webResponse2 = httpWebRequest2.GetResponse();
        //error returned from getResponse: "The remote server returned an error: (405) Method Not Allowed."
        //I guess cause my folder is in read only

        Stream stream2 = webResponse2.GetResponseStream();
        StreamReader reader2 = new StreamReader(stream2);

        MessageBox.Show(reader2.ReadToEnd());

        webResponse2.Close();
        httpWebRequest2 = null;
        webResponse2 = null; 

    }

首先我得到这个错误：远程服务器返回一个错误：（405）方法不允许。所以我尝试通过在网站上添加映射来启用 POST。

现在在 te 服务器上的文件夹中，我有一个 web.config 文件，即：

    <?xml version="1.0" encoding="UTF-8"?>
 <configuration>
    <system.webServer>
    <directoryBrowse enabled="true" />
    <handlers>
        <add name="File TXT" path="*.*" verb="*" modules="IsapiModule" scriptProcessor="C:\Windows\System32\inetsrv\asp.dll" resourceType="Unspecified" requireAccess="Script" preCondition="bitness64" />
    </handlers>
</system.webServer>
</configuration>

这样我没有收到任何错误，但应用程序没有上传任何文件。我该如何解决这个问题？

4

2 回答 2

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一个更简单的解决方案是使用 System.Net.Webclient 类来上传文件。

System.Net.WebClient client = new System.Net.WebClient();

client.UploadFile("www.myfileuploadendpoint.com",@"c:\myfiletoupload.txt");

客户端还有一个 OnUploadFileCompleted 事件，该事件将在完成后调用处理程序。

client.OnUploadFileCompleted  += UploadCompleted(sender,args) => { //do whatever you want}

这将节省您的代码和错误。祝你好运！:)

于 2012-10-24T10:01:54.267 回答
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上述两个示例都不起作用，

  1. “远程服务器返回错误：(405) Method Not Allowed。” 是在尝试上述两个代码时发现的异常

期待有人分享他们对这些例外的想法，拜托。

rgds, 蒂鲁

于 2013-12-11T06:19:08.103 回答