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几天来一直在尝试使用 twitter4j 发布推文，但没有运气，我想做的是让一个人在一轮结束时从应用程序的时间线上发布他们的新最高分。这是我的代码

          @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_tweetr);
    Button tweetr = (Button)findViewById(R.id.tweetr);

    //create a new twitter configuration using user details
    tweetTwitter = new TwitterFactory().getInstance();
    tweetTwitter.setOAuthConsumer(TWIT_KEY, TWIT_SECRET);


        //create a twitter instance
   // tweetTwitter = new TwitterFactory(twitConf).getInstance();



    tweetr.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {


          dt.execute();

        }
    });



}


public class TweetTask extends AsyncTask<Object, Void, String> {
    @Override
    protected String doInBackground(Object... values) {
        /* try {
            //requestToken = tweetTwitter.getOAuthRequestToken(TWITTER_CALLBACK_URL);
        } catch (TwitterException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(requestToken.getAuthenticationURL())));
        */
        try {
            requestToken = tweetTwitter.getOAuthRequestToken(TWITTER_CALLBACK_URL);
            String authUrl = requestToken.getAuthenticationURL();
            startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(authUrl)));
        } catch (TwitterException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


      return null;
    }


    @Override
    protected void onPostExecute(String result) {
        Log.d("URI", "DONE");
        super.onPostExecute(result);
    }




}



@Override
protected void onResume() {
    super.onResume();
    final Uri uri = getIntent().getData();
    if(uri != null ){

                Log.d("URI", uri.toString());

                Thread th = new Thread(){
                    public void run(){
                        try {
                            String verifier = uri.getQueryParameter("oauth_verifier");
                            String oauthToken = uri.getQueryParameter("oauth_token");

                            RequestToken reqToken = tweetTwitter.getOAuthRequestToken(oauthToken,verifier); 


                            AccessToken accessToken = tweetTwitter.getOAuthAccessToken(reqToken);
                            String token = accessToken.getToken(), secret = accessToken.getTokenSecret();

                        } catch (TwitterException ex) {
                            Log.e("Main.onNewIntent", "" + ex.getMessage());
                        }


                    }};
                    th.start();
      }else
        Log.d("URI", "FAILED");         


    }

}

这是我的错误打印出来

10-23 15:35:18.661: D/TWIT ER(2392): No authentication challenges foundRelevant discussions can be found on the Internet at:
4

1 回答 1

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参考Twitter4J的javadoc

In order to get access acquire AccessToken using xAuth, you must apply by sending an email to api@twitter.com — all other applications will receive an HTTP 401 error.
于 2012-10-24T02:49:52.520 回答