259

有没有办法在不使用 try/catch 块的情况下检查文件是否被锁定？

现在，我知道的唯一方法就是打开文件并捕获任何System.IO.IOException.

4

12 回答 12

185

当我遇到类似的问题时，我完成了以下代码：

public class FileManager
{
    private string _fileName;

    private int _numberOfTries;

    private int _timeIntervalBetweenTries;

    private FileStream GetStream(FileAccess fileAccess)
    {
        var tries = 0;
        while (true)
        {
            try
            {
                return File.Open(_fileName, FileMode.Open, fileAccess, Fileshare.None); 
            }
            catch (IOException e)
            {
                if (!IsFileLocked(e))
                    throw;
                if (++tries > _numberOfTries)
                    throw new MyCustomException("The file is locked too long: " + e.Message, e);
                Thread.Sleep(_timeIntervalBetweenTries);
            }
        }
    }

    private static bool IsFileLocked(IOException exception)
    {
        int errorCode = Marshal.GetHRForException(exception) & ((1 << 16) - 1);
        return errorCode == 32 || errorCode == 33;
    }

    // other code

}
于 2010-07-08T09:12:36.160 回答
153

其他答案依赖于旧信息。这提供了一个更好的解决方案。

很久以前，不可能可靠地获取锁定文件的进程列表，因为 Windows 根本不跟踪该信息。为了支持Restart Manager API，现在跟踪该信息。重新启动管理器 API 从 Windows Vista 和 Windows Server 2008 开始可用（重新启动管理器：运行时要求）。

List<Process>我将获取文件路径并返回锁定该文件的所有进程的代码放在一起。

static public class FileUtil
{
    [StructLayout(LayoutKind.Sequential)]
    struct RM_UNIQUE_PROCESS
    {
        public int dwProcessId;
        public System.Runtime.InteropServices.ComTypes.FILETIME ProcessStartTime;
    }

    const int RmRebootReasonNone = 0;
    const int CCH_RM_MAX_APP_NAME = 255;
    const int CCH_RM_MAX_SVC_NAME = 63;

    enum RM_APP_TYPE
    {
        RmUnknownApp = 0,
        RmMainWindow = 1,
        RmOtherWindow = 2,
        RmService = 3,
        RmExplorer = 4,
        RmConsole = 5,
        RmCritical = 1000
    }

    [StructLayout(LayoutKind.Sequential, CharSet = CharSet.Unicode)]
    struct RM_PROCESS_INFO
    {
        public RM_UNIQUE_PROCESS Process;

        [MarshalAs(UnmanagedType.ByValTStr, SizeConst = CCH_RM_MAX_APP_NAME + 1)]
        public string strAppName;

        [MarshalAs(UnmanagedType.ByValTStr, SizeConst = CCH_RM_MAX_SVC_NAME + 1)]
        public string strServiceShortName;

        public RM_APP_TYPE ApplicationType;
        public uint AppStatus;
        public uint TSSessionId;
        [MarshalAs(UnmanagedType.Bool)]
        public bool bRestartable;
    }

    [DllImport("rstrtmgr.dll", CharSet = CharSet.Unicode)]
    static extern int RmRegisterResources(uint pSessionHandle,
                                          UInt32 nFiles,
                                          string[] rgsFilenames,
                                          UInt32 nApplications,
                                          [In] RM_UNIQUE_PROCESS[] rgApplications,
                                          UInt32 nServices,
                                          string[] rgsServiceNames);

    [DllImport("rstrtmgr.dll", CharSet = CharSet.Auto)]
    static extern int RmStartSession(out uint pSessionHandle, int dwSessionFlags, string strSessionKey);

    [DllImport("rstrtmgr.dll")]
    static extern int RmEndSession(uint pSessionHandle);

    [DllImport("rstrtmgr.dll")]
    static extern int RmGetList(uint dwSessionHandle,
                                out uint pnProcInfoNeeded,
                                ref uint pnProcInfo,
                                [In, Out] RM_PROCESS_INFO[] rgAffectedApps,
                                ref uint lpdwRebootReasons);

    /// <summary>
    /// Find out what process(es) have a lock on the specified file.
    /// </summary>
    /// <param name="path">Path of the file.</param>
    /// <returns>Processes locking the file</returns>
    /// <remarks>See also:
    /// http://msdn.microsoft.com/en-us/library/windows/desktop/aa373661(v=vs.85).aspx
    /// http://wyupdate.googlecode.com/svn-history/r401/trunk/frmFilesInUse.cs (no copyright in code at time of viewing)
    /// 
    /// </remarks>
    static public List<Process> WhoIsLocking(string path)
    {
        uint handle;
        string key = Guid.NewGuid().ToString();
        List<Process> processes = new List<Process>();

        int res = RmStartSession(out handle, 0, key);

        if (res != 0)
            throw new Exception("Could not begin restart session.  Unable to determine file locker.");

        try
        {
            const int ERROR_MORE_DATA = 234;
            uint pnProcInfoNeeded = 0,
                 pnProcInfo = 0,
                 lpdwRebootReasons = RmRebootReasonNone;

            string[] resources = new string[] { path }; // Just checking on one resource.

            res = RmRegisterResources(handle, (uint)resources.Length, resources, 0, null, 0, null);

            if (res != 0) 
                throw new Exception("Could not register resource.");                                    

            //Note: there's a race condition here -- the first call to RmGetList() returns
            //      the total number of process. However, when we call RmGetList() again to get
            //      the actual processes this number may have increased.
            res = RmGetList(handle, out pnProcInfoNeeded, ref pnProcInfo, null, ref lpdwRebootReasons);

            if (res == ERROR_MORE_DATA)
            {
                // Create an array to store the process results
                RM_PROCESS_INFO[] processInfo = new RM_PROCESS_INFO[pnProcInfoNeeded];
                pnProcInfo = pnProcInfoNeeded;

                // Get the list
                res = RmGetList(handle, out pnProcInfoNeeded, ref pnProcInfo, processInfo, ref lpdwRebootReasons);

                if (res == 0)
                {
                    processes = new List<Process>((int)pnProcInfo);

                    // Enumerate all of the results and add them to the 
                    // list to be returned
                    for (int i = 0; i < pnProcInfo; i++)
                    {
                        try
                        {
                            processes.Add(Process.GetProcessById(processInfo[i].Process.dwProcessId));
                        }
                        // catch the error -- in case the process is no longer running
                        catch (ArgumentException) { }
                    }
                }
                else
                    throw new Exception("Could not list processes locking resource.");                    
            }
            else if (res != 0)
                throw new Exception("Could not list processes locking resource. Failed to get size of result.");                    
        }
        finally
        {
            RmEndSession(handle);
        }

        return processes;
    }
}

更新

这是另一个关于如何使用 Restart Manager API 的示例代码讨论。

于 2013-12-16T23:47:30.900 回答
132

不，不幸的是，如果您考虑一下，无论如何该信息将毫无价值，因为文件可能会在下一秒被锁定（阅读：短时间跨度）。

为什么特别需要知道文件是否被锁定？知道这可能会给我们一些其他的方式来给你很好的建议。

如果您的代码如下所示：

if not locked then
    open and update file

然后在这两行之间，另一个进程可以轻松地锁定文件，给你同样的问题，你试图避免开始：异常。

于 2008-08-04T14:59:24.410 回答
16

您还可以检查是否有任何进程正在使用此文件，并显示您必须关闭才能继续的程序列表，就像安装程序一样。

public static string GetFileProcessName(string filePath)
{
    Process[] procs = Process.GetProcesses();
    string fileName = Path.GetFileName(filePath);

    foreach (Process proc in procs)
    {
        if (proc.MainWindowHandle != new IntPtr(0) && !proc.HasExited)
        {
            ProcessModule[] arr = new ProcessModule[proc.Modules.Count];

            foreach (ProcessModule pm in proc.Modules)
            {
                if (pm.ModuleName == fileName)
                    return proc.ProcessName;
            }
        }
    }

    return null;
}
于 2011-04-01T11:19:20.407 回答
13

您可以使用 .NET FileStream 类方法 Lock 和 Unlock，而不是使用互操作：

FileStream.Lock http://msdn.microsoft.com/en-us/library/system.io.filestream.lock.aspx

FileStream.Unlock http://msdn.microsoft.com/en-us/library/system.io.filestream.unlock.aspx

于 2010-03-08T17:09:15.270 回答
8

DixonD 出色答案的变体（上图）。

public static bool TryOpen(string path,
                           FileMode fileMode,
                           FileAccess fileAccess,
                           FileShare fileShare,
                           TimeSpan timeout,
                           out Stream stream)
{
    var endTime = DateTime.Now + timeout;

    while (DateTime.Now < endTime)
    {
        if (TryOpen(path, fileMode, fileAccess, fileShare, out stream))
            return true;
    }

    stream = null;
    return false;
}

public static bool TryOpen(string path,
                           FileMode fileMode,
                           FileAccess fileAccess,
                           FileShare fileShare,
                           out Stream stream)
{
    try
    {
        stream = File.Open(path, fileMode, fileAccess, fileShare);
        return true;
    }
    catch (IOException e)
    {
        if (!FileIsLocked(e))
            throw;

        stream = null;
        return false;
    }
}

private const uint HRFileLocked = 0x80070020;
private const uint HRPortionOfFileLocked = 0x80070021;

private static bool FileIsLocked(IOException ioException)
{
    var errorCode = (uint)Marshal.GetHRForException(ioException);
    return errorCode == HRFileLocked || errorCode == HRPortionOfFileLocked;
}

用法：

private void Sample(string filePath)
{
    Stream stream = null;

    try
    {
        var timeOut = TimeSpan.FromSeconds(1);

        if (!TryOpen(filePath,
                     FileMode.Open,
                     FileAccess.ReadWrite,
                     FileShare.ReadWrite,
                     timeOut,
                     out stream))
            return;

        // Use stream...
    }
    finally
    {
        if (stream != null)
            stream.Close();
    }
}
于 2013-01-03T03:41:42.223 回答
7

这是 DixonD 代码的变体，它增加了等待文件解锁的秒数，然后重试：

public bool IsFileLocked(string filePath, int secondsToWait)
{
    bool isLocked = true;
    int i = 0;

    while (isLocked &&  ((i < secondsToWait) || (secondsToWait == 0)))
    {
        try
        {
            using (File.Open(filePath, FileMode.Open)) { }
            return false;
        }
        catch (IOException e)
        {
            var errorCode = Marshal.GetHRForException(e) & ((1 << 16) - 1);
            isLocked = errorCode == 32 || errorCode == 33;
            i++;

            if (secondsToWait !=0)
                new System.Threading.ManualResetEvent(false).WaitOne(1000);
        }
    }

    return isLocked;
}


if (!IsFileLocked(file, 10))
{
    ...
}
else
{
    throw new Exception(...);
}
于 2013-09-24T18:34:18.777 回答
5

您可以通过互操作在您感兴趣的文件区域上调用LockFile。这不会引发异常，如果成功，您将锁定文件的该部分（由您的进程持有），该锁定将是一直保留到您调用UnlockFile或您的进程终止。

于 2009-07-24T06:42:10.800 回答
4

然后在这两行之间，另一个进程可以轻松地锁定文件，给你同样的问题，你试图避免开始：异常。

但是，通过这种方式，您会知道问题是暂时的，并稍后重试。（例如，您可以编写一个线程，如果在尝试写入时遇到锁，则继续重试直到锁消失。）

另一方面，IOException 本身并不够具体，以至于锁定是导致 IO 失败的原因。可能有一些不是暂时的原因。

于 2008-08-17T18:17:12.937 回答
4

您可以通过自己尝试读取或锁定文件来查看文件是否被锁定。

请在此处查看我的答案以获取更多信息。

于 2009-03-09T12:54:57.213 回答
0

同样的事情，但在 Powershell 中

function Test-FileOpen
{
    Param
    ([string]$FileToOpen)
    try
    {
        $openFile =([system.io.file]::Open($FileToOpen,[system.io.filemode]::Open))
        $open =$true
        $openFile.close()
    }
    catch
    {
        $open = $false
    }
    $open
}
于 2015-12-23T14:24:09.253 回答
-1

我最终做的是：

internal void LoadExternalData() {
    FileStream file;

    if (TryOpenRead("filepath/filename", 5, out file)) {
        using (file)
        using (StreamReader reader = new StreamReader(file)) {
         // do something 
        }
    }
}


internal bool TryOpenRead(string path, int timeout, out FileStream file) {
    bool isLocked = true;
    bool condition = true;

    do {
        try {
            file = File.OpenRead(path);
            return true;
        }
        catch (IOException e) {
            var errorCode = Marshal.GetHRForException(e) & ((1 << 16) - 1);
            isLocked = errorCode == 32 || errorCode == 33;
            condition = (isLocked && timeout > 0);

            if (condition) {
                // we only wait if the file is locked. If the exception is of any other type, there's no point on keep trying. just return false and null;
                timeout--;
                new System.Threading.ManualResetEvent(false).WaitOne(1000);
            }
        }
    }
    while (condition);

    file = null;
    return false;
}
于 2013-12-16T19:19:18.057 回答