我有一个如下实体列表。
Entity1 { Id=1, From=01/01/2011, To=31/01/2011, Status=true }
Entity2 { Id=1, From=01/02/2011, To=28/02/2011, Status=false}
Entity2 { Id=2, From=01/02/2011, To=28/02/2011, Status=false}
Entity3 { Id=3, From=01/01/2011, To=31/01/2011, Status=true }
Entity4 { Id=4, From=01/01/2011, To=31/01/2011, Status=true }
Entity5 { Id=1, From=01/03/2011, To=31/03/2011, Status=false}
Entity6 { Id=4, From=31/03/2011, To=10/04/2011, Status=false}
我想找到具有最旧日期和最晚日期的实体。(实体涵盖从日期到至今的全部内容)
基本上我需要获取与日期不同的实体。此外,起始实体应具有最早的起始日期,最终实体应具有最新的截止日期
在这种情况下,预期结果是从01/01/2011到10/04/2011的实体。
更新
Entity 1 has the oldest from date : 01/01/2011
Entiry 2 which falls under : 01/01/2011 and 10/04/2011
Entity 3 which falls under 01/01/2011 and 10/04/2011(but entity 1 has same from and to date as Entity3 so entity 3 not a valid)
Entity 4 which falls under 01/01/2011 and 10/04/2011(but entity 1 has same from and to date as Entity4 so entity 4 not a valid)
Entity 5 which falls under : 01/01/2011 and 10/04/2011
Entity 6 has the most recent To date : 10/04/2011
So Valid entries are Entity1, Entity2, Entity5, Entity6
我尝试过这样的事情
var dates = (EntityList.GroupBy(offer => offer.id)
.Select(group =>
new { offerid = group.Key,
offers = group.OrderBy(o => o.From)
})
.OrderBy(g => g.offers.First().From)
. FirstOrDefault
().offers.First();
但我认为它应该不分组,但我不太确定
任何帮助表示赞赏
谢谢