118

我想拥有来自同一数据条目的版本。换句话说，我想用另一个版本号复制条目。

id - Version将是主键。

实体应该是什么样子？如何将其复制到另一个版本？

id Version ColumnA

1   0      Some data
1   1      Some Other data
2   0      Data 2. Entry
2   1      Data
4

4 回答 4

255

您可以创建一个Embedded class包含您的两个键的 ，然后像EmbeddedId在您的Entity.

您将需要@EmbeddedIdand@Embeddable注释。

@Entity
public class YourEntity {
    @EmbeddedId
    private MyKey myKey;

    @Column(name = "ColumnA")
    private String columnA;

    /** Your getters and setters **/
}

@Embeddable
public class MyKey implements Serializable {

    @Column(name = "Id", nullable = false)
    private int id;

    @Column(name = "Version", nullable = false)
    private int version;

    /** getters and setters **/
}

完成此任务的另一种方法是使用@IdClass注释，并将两者都id放在IdClass. 现在您可以@Id在两个属性上使用普通注释

@Entity
@IdClass(MyKey.class)
public class YourEntity {
   @Id
   private int id;
   @Id
   private int version;

}


public class MyKey implements Serializable {
   private int id;
   private int version;
}
于 2012-10-23T14:42:10.127 回答
11

Serializable如果您正在使用MyKey 类必须实现@IdClass

于 2015-09-24T06:45:50.407 回答
5

关键类：

@Embeddable
@Access (AccessType.FIELD)
public class EntryKey implements Serializable {

    public EntryKey() {
    }

    public EntryKey(final Long id, final Long version) {
        this.id = id;
        this.version = version;
    }

    public Long getId() {
        return this.id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public Long getVersion() {
        return this.version;
    }

    public void setVersion(Long version) {
        this.version = version;
    }

    public boolean equals(Object other) {
        if (this == other)
            return true;
        if (!(other instanceof EntryKey))
            return false;
        EntryKey castOther = (EntryKey) other;
        return id.equals(castOther.id) && version.equals(castOther.version);
    }

    public int hashCode() {
        final int prime = 31;
        int hash = 17;
        hash = hash * prime + this.id.hashCode();
        hash = hash * prime + this.version.hashCode();
        return hash;
    }

    @Column (name = "ID")
    private Long id;
    @Column (name = "VERSION")
    private Long operatorId;
}

实体类：

@Entity
@Table (name = "YOUR_TABLE_NAME")
public class Entry implements Serializable {

    @EmbeddedId
    public EntryKey getKey() {
        return this.key;
    }

    public void setKey(EntryKey id) {
        this.id = id;
    }

    ...

    private EntryKey key;
    ...
}

如何将其复制到另一个版本？

您可以分离从提供者检索到的实体，更改 Entry 的键，然后将其作为新实体保存。

于 2012-10-23T14:52:14.833 回答
2

MyKey 类（@Embeddable）不应该有任何像 @ManyToOne 这样的关系

于 2017-07-11T01:15:22.457 回答