0

我在 codeigniter 中设置这个函数作为 cron 作业运行并在 X 时间注销所有用户。在选择一个用户并将该用户注销时，我已成功使用此代码，但是在添加 foreach 时，出现以下错误：

Error Number: 1062

Duplicate entry '3858' for key 'PRIMARY'

INSERT INTO `time` (`id`, `projectid`, `phaseid`, `firstname`, `timest`, `status`, `activityid`, `todate`, `remark`, `time`, `workperiod`, `activitydate`, `entrydate`) VALUES ('3858', '212132 Unilever Nigeria  10000L Toothpaste Storage Tanks x 2', '1', 'BONGANI', '1347610976', '1', '1', '1', '1', 3335907, 'nothing', '2012-09-14 10:22:56', '2012-10-23 01:01:23')

Filename: C:\xampp\htdocs\projectfiles\protime\v2\system\database\DB_driver.php

Line Number: 330

这是模型的代码：

function punch_out() {
    $this -> load -> database();
    $this -> load -> helper('date');
    //get people
    $this -> db -> select('*');
    $this -> db -> from('person');
    $this -> db -> order_by("department", "asc");
    $this -> db -> order_by("userid", "asc");
    $query = $this -> db -> get();
    foreach ($query->result_array() as $row) {
        $people[] = $row;

    }

    foreach ($people as $row) :

    $this -> db -> from('punch');
    $this -> db -> where('firstname', $row['firstname']);
    $this -> db -> order_by("id", "desc");
    $this -> db -> limit(1);
    $query = $this -> db -> get();
    foreach ($query->result_array() as $row) {
        $data = $row;
    }

    $data['workperiod'] = 'nothing';

    $current_time = getdate();

    if ($current_time['wday'] > '0' && $current_time['wday'] < '5') {
        if ($current_time['hours'] > '7' && $current_time['hours'] < '12') {
            $data['workperiod'] = 'stda';
        } else if ($current_time['0'] > strtotime('4:16am') && $current_time < strtotime('11:59pm')) {
            $data['workperiod'] = 'ota';
        }
    } else if ($current_time['wday'] == '5') {
        if ($current_time['0'] > strtotime('7:00am') && $current_time < strtotime('11:59am')) {
            $data['workperiod'] = 'stdb';
        } else if ($current_time['0'] > strtotime('1:01am') && $current_time < strtotime('11:59pm')) {
            $data['workperiod'] = 'otb';
        }
    } else if ($current_time['wday'] == '6') {
        $data['workperiod'] = 'otc';
    } else if ($current_time['wday'] == '0') {
        $data['workperiod'] = 'dtc';
    }

    if ($data['status'] == 1) {
        //MAKE TIME
        $now = time();
        $data['time'] = elapsed_time($data['timest'], $now);
        $data['entrydate'] = timestamp_to_mysqldatetime($now);
        $data['activitydate'] = timestamp_to_mysqldatetime($data['timest']);
        $this -> db -> insert('time', $data);
    }

    endforeach;
}
4

2 回答 2

1

如果您尝试更新您插入的同一 id 的数据（时间、入口日期、活动日期），我认为如果您只将数据放入一个新数组中会更好，例如：

if ($data['status'] == 1) {
    //MAKE TIME
    $now = time();
    $newdata['time'] = elapsed_time($data['timest'], $now);
    $newdata['entrydate'] = timestamp_to_mysqldatetime($now);
    $newdata['activitydate'] = timestamp_to_mysqldatetime($data['timest']);
    $this -> db -> where('id',$data['id']);
    $this -> db -> update('time', $newdata);
}

或者，如果您尝试将新记录插入数据库，只需更改您尝试插入的数组名称：

if ($data['status'] == 1) {
    //MAKE TIME
    $now = time();
    $newdata['time'] = elapsed_time($data['timest'], $now);
    $newdata['entrydate'] = timestamp_to_mysqldatetime($now);
    $newdata['activitydate'] = timestamp_to_mysqldatetime($data['timest']);
    $this -> db -> insert('time', $newdata);
}

以这种编码方式，这可能会避免将来出现更多错误并可能节省时间。

干杯!

于 2012-10-23T02:29:59.613 回答
0

如果我没看错的话，$data它会包含每个“拳头”的详细信息，包括$data['id']那个拳头的唯一 ID。由于您永远不会从 中删除该$data['id']字段$data，因此当您将条目插入到time数据库中时$data，您还指定新条目与id您从中提取的打孔相同。一旦您尝试运行两次，您将插入两行相同的id，并且从您的错误看来，您将表id上的time字段设置为 PRIMARY - 这意味着它不能有任何重复项。

我认为，如果我正确理解了您的代码和数据结构，则解决方案是unset($data['id'])在运行插入之前。

于 2012-10-22T23:23:34.037 回答