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CREATE TABLE IF NOT EXISTS `site_location` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `level` int(11) NOT NULL,
  `lft` int(11) NOT NULL,
  `rgt` int(11) NOT NULL,
  `name` varchar(50) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=13 ;

///DATA
    INSERT INTO `site_location` (`id`, `level`, `lft`, `rgt`, `name`) VALUES
    (1, 0, 1, 24, 'United Kingdom'),
    (2, 1, 2, 19, 'London'),
    (3, 2, 13, 14, 'Central London'),
    (4, 2, 11, 12, 'East London'),
    (5, 2, 9, 10, 'North London'),
    (6, 2, 7, 8, 'North West London'),
    (7, 2, 5, 6, 'South East London'),
    (8, 2, 3, 4, 'West London'),
    (9, 2, 15, 18, 'South West'),
    (10, 3, 16, 17, 'Battersea'),
    (11, 1, 20, 23, 'Brighton'),
    (12, 2, 21, 22, 'Guildford');

CREATE TABLE IF NOT EXISTS `ads` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `category_id` int(11) NOT NULL,
  `location` int(11) NOT NULL,
  `title` varchar(255) CHARACTER SET utf8 NOT NULL,
  PRIMARY KEY (`id`,`category_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ;

INSERT INTO `ads` (`id`, `category_id`, `location`, `title`) VALUES
(1, 7, 10, 'Test1'),
(2, 9, 3, 'Test2'),
(3, 12, 10, 'Test3'),
(4, 13, 4, 'Test4');

当 ID 为 ID=1 时以这种方式返回

[ United Kingdom(4) ]
    London(4)     
    Brighton(0)

当 ID 为 ID = 2

    United Kingdom(4)
      [ London(4) ]
        South West(2)
        Central London(1)
        East London(1)
      Brighton(0)

so when is selected "London" I need all its siblings and all its children

选择“西南”时相同，我需要它的所有兄弟姐妹所有它的孩子，它的父母所有它的父母兄弟姐妹

    United Kingdom(4)
      London(4)
        [ South West(2) ]
          Battersea(2)
        Central London(1)
        East London(1)
      Brighton(0)

以及该位置有多少广告，例如在英国必须有 4 个，因为表格中的所有广告都是 4 个，西南必须有 2 个，因为在巴特西有 2 个

当 id 为 11 时

United Kingdom(4)
  London(4)
  [ Brighton(0) ]
      Guildford(0)

我有一个查询：西南 lft:15, rgt:18, level:2

 SELECT 
    node.id, 
    node.alias, 
    node.level, 
    node.name, 
    COUNT(ads.id) as ads,
    IF(node.lft = node.rgt-1, "0", "1") AS `has_children`
 FROM 
    site_location AS parent LEFT JOIN
    ads as ads ON (parent.id = ads.location),
    site_location AS node
 WHERE
    parent.lft BETWEEN node.lft AND node.rgt
 AND 
    parent.lft BETWEEN 15 AND 18
 AND 
    node.level > 0
 AND
   node.level < 2 + 3
 GROUP BY node.id
 ORDER BY node.lft

这将返回

 London(4)
  South West(2)
   Battersea(2)

我需要这样

 London(4)
  South West(2)
   Battersea(2)
 Brighton(0)

是否可以通过单个查询来做到这一点：？如果有人可以提供帮助，那就太好了。提前致谢！

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