-1

我想获取从当前日期到明年当前日期的 Facebook 朋友生日。todate 是 364 天后到现在的日期,以 m/d 为单位。为此,第一个 fql 用于检索从 1 月到当前日期的数据,第二个用于获取从当前日期到 12 月 31 日的数据。我想在接下来的 11 个月和 29 天为即将到来的生日应用分页。以下查询正在工作并获取数据。谁能告诉我最好的方法。任何建议将不胜感激。

$fromDate = date('m/d');
$past_birthdays = $facebook->api(array(
                'method' => 'fql.query',
                'query' => "SELECT uid, name, birthday, birthday_date,substr(birthday_date,0,3) FROM user WHERE uid IN (SELECT uid2 FROM friend WHERE uid1 = me()) AND birthday_date<'$toDate' AND birthday_date>='01/01' order by birthday_date",
                'access_token' => $accessToken
                    ));
if ($toDate > $fromDate) {
            $condition = " AND birthday_date<'$toDate'";
        } else {
            $condition = "";
        }

$upcoming_birthdays = $facebook->api(array(
                'method' => 'fql.query',
                'query' => "SELECT uid, name, birthday, birthday_date,substr(birthday_date,0,3) FROM user WHERE uid IN (SELECT uid2 FROM friend WHERE uid1 = me()) AND birthday_date>='$fromDate' $condition order by birthday_date",
                'access_token' => $accessToken
                    ));
4

1 回答 1

1

就像你的情况一样,如果你在查询中提供限制,那么我在 facebook api explorer 上检查过,然后它的输出不一致,解决你的问题的最佳方法是将整个生日列表加载到数组中并将其显示在插槽中。

$fromDate = date('m/d');
        $past_birthdays = "";
        $upcoming_birthdays = $facebook->api(array(
            'method' => 'fql.query',
            'query' => "SELECT uid, name, birthday, birthday_date, substr(birthday_date, 0,3) from user where uid in (select uid2 from friend where uid1=me()) and birthday_date >='$fromDate' order by birthday_date Limit 0,500",
            'access_token' => $accessToken
                ));
        $no = count($upcoming_birthdays); //exit;
        if ($no < 500) {
            $Limit2 = 500 - $no;
            $past_birthdays = $facebook->api(array(
                'method' => 'fql.query',
                'query' => "SELECT uid, name, birthday, birthday_date, substr(birthday_date, 0,3) from user where uid in (select uid2 from friend where uid1=me()) and birthday_date >='01/01' and birthday_date <= '$fromDate' order by birthday_date Limit 0,$Limit2",
                'access_token' => $accessToken
                    ));
            //echo count($past_birthdays);exit;
            $upcoming_birthdays = array_merge($upcoming_birthdays, $past_birthdays);

无需获取 todate,因为您要获取全年。此 ccode 仅获取 500,但全年运行查询。

于 2012-11-07T14:19:01.563 回答