我得到一个 ClassCastException。我想知道我在这里做错了什么。做一个(RegistrationRequest)(element.getValue())
应该有效的。我知道(RegistrationRequest)element.getValue()
可能没有。
SEVERE: Servlet.service() for servlet [Jersey REST Service] in context with path [/mCruiseOnCarPool4All] threw exception
java.lang.ClassCastException: com.sun.org.apache.xerces.internal.dom.ElementNSImpl cannot be cast to com.mcruiseon.common.message.request.RegistrationRequest
服务器 Post 方法,注意方法签名中的 JAXBElement。我正在对它进行类型转换clientSession.waitAndGetResponse((RegistrationRequest)(element.getValue())) ;
。这是我得到异常的行号。
@POST
@Path ("Request")
@Consumes({ MediaType.APPLICATION_JSON })
public Response post(JAXBElement<Object> element) {
AMessageStrategy response ;
try {
clientSession = new ClientSession(God.mCruiseOnServer) ;
} catch (InvalidServerDNSorIPException e) {
e.printStackTrace();
return Response.serverError().build() ;
}
sessionKey = sessionManager.setClientSession(clientSession) ;
clientSession.setSessionKey(sessionKey) ;
clientSession.getSendQueue().sendRequest((RegistrationRequest)(element.getValue()));
try {
response = clientSession.waitAndGetResponse((RegistrationRequest)(element.getValue())) ;
} catch (WaitedLongEnoughException e) {
return Response.serverError().build() ;
} catch (UnableToResolveResponseException e) {
return Response.serverError().build() ;
}
return Response.ok(response).build();
}
客户端是一个junit测试用例,相关部分代码是
ClientIdentityConcrete clientIdentity = new ClientIdentityConcrete("username", "password", "secretkey") ;
RegistrationRequest register = new RegistrationRequest(clientIdentity);
String jsonStr = mapper.writeValueAsString(clientIdentity);
HttpPost request = new HttpPost("http://localhost:8081/mCruiseOnCarPool4All/carpool4all/Registration/Request");
StringEntity se = new StringEntity(jsonStr);
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
request.setEntity(se);
HttpResponse response = client.execute(request);