23

我正在尝试使用 Amazon 的 AWSSDK for C# 和简单通知服务进行发布。

SDK 没有附带任何示例，在谷歌搜索 2 小时后，我在网络上的任何地方都找不到示例。我想出了这个，但它抛出了一个异常，它产生的信息不超过单个字符串“TopicARN”——没有内部异常——nuffin！
如果有人使用AWSSDKSNS通过 C#成功发送消息，我希望看到即使是最基本的工作示例。我正在使用最新的 SDK 1.5x

这是代码：

string resourceName = "arn:aws:sns:us-east-1:xxxxxxxxxxxx:StackOverFlowStub";
AmazonSimpleNotificationServiceClient snsclient = new AmazonSimpleNotificationServiceClient(accesskey,secretkey);
AddPermissionRequest permissionRequest = new AddPermissionRequest()
                .WithActionNames("Publish")
                .WithActionNames(accesskey)
                .WithActionNames("PrincipleAllowControl")
                .WithActionNames(resourceName);
snsclient.AddPermission(permissionRequest);

PublishRequest pr = new PublishRequest();
pr.WithMessage("Test Msg");
pr.WithTopicArn(resourceName);
pr.WithSubject("Test Subject");
snsclient.Publish(pr);
4

1 回答 1

29

这是一个创建主题、设置主题显示名称、订阅主题的电子邮件地址、发送消息和删除主题的示例。请注意，在继续之前，您应该在两个地方等待/检查您的电子邮件。Client是客户端实例，topicName是任意主题名称。

// Create topic
string topicArn = client.CreateTopic(new CreateTopicRequest
{
    Name = topicName
}).CreateTopicResult.TopicArn;

// Set display name to a friendly value
client.SetTopicAttributes(new SetTopicAttributesRequest
{
    TopicArn = topicArn,
    AttributeName = "DisplayName",
    AttributeValue = "StackOverflow Sample Notifications"
});

// Subscribe an endpoint - in this case, an email address
client.Subscribe(new SubscribeRequest
{
    TopicArn = topicArn,
    Protocol = "email",
    Endpoint = "sample@example.com"
});

// When using email, recipient must confirm subscription
Console.WriteLine("Please check your email and press enter when you are subscribed...");
Console.ReadLine();

// Publish message
client.Publish(new PublishRequest
{
    Subject = "Test",
    Message = "Testing testing 1 2 3",
    TopicArn = topicArn
});

// Verify email receieved
Console.WriteLine("Please check your email and press enter when you receive the message...");
Console.ReadLine();

// Delete topic
client.DeleteTopic(new DeleteTopicRequest
{
    TopicArn = topicArn
});
于 2012-10-22T17:43:12.727 回答