我当前的 LINQ 查询和示例 XML 如下。我想做的是从 以及其他属性(如修剪、身体、品牌、型号等)中选择主要图像 url。
做这个的最好方式是什么?
<response>
<objects>
<object>
<trim>LT</trim>
<body>4dr Car</body>
<warranty_miles />
<color>WHITE</color>
<selling_price>0.00</selling_price>
<vin>1g1jc5sh3c4198042</vin>
<has_service_contract >False</has_service_contract>
<year>2012</year>
<alt_id></alt_id>
<stock_num>1205362</stock_num>
<has_warranty>False</has_warranty>
<warranty_month />
<make>CHEVROLET</make>
<date_manufactured />
<interior_color>Dark Pewter/Dark Titanium</interior_color>
<date_updated>2012-10-17</date_updated>
<date_dealer_created>2012-06-06</date_dealer_created>
<certification_warranty />
<status/>
<vevo></vevo>
<image_urls>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/1764e186eabe4ae892f6230107b862cf.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/3eeb7050770849e8937191d09453d936.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/7f6c1f172f7b4944ac2d165c0dfbcb09.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/82d242ba07bb4bb9a7c8514ea1aadae7.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/93e3cac89d0f4872b86acd9c2d94695a.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/edec4ffe9b2349ffabea9dcb25a78d1e.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/f2c1dbb15fec4cf6a62b7842db22763a.jpg</url>
<resource_uri></resource_uri>
</object>
<object>
<url>http://content.homenetiol.com/1593/69025/640x480/fa7341e250654533a9de2a756d4274eb.jpg</url>
<resource_uri></resource_uri>
</object>
</image_urls>
</object>
</objects>
</response>
这是我到目前为止所拥有的
var users = from m in main2.Elements("object")
select new Inventory
{
Make = (string)m.Element("make"),
Year = (string)m.Element("year"),
Model = (string)m.Element("model"),
};