php - 无法在php mysql中同时将相同的数据插入2个表中

Question

我需要你的帮助来解决我的问题。首先我在 mysql dbase 中有 2 个表。这里是结构：

doctor1:
--------                         
no_que autoincrement pk,
doctor_name,
id_patient,
date,
time

status_que:
----------
id_patient,
doctor_name,
no_que fk,
date,
time

我想将数据插入到 doctor1 中，status_que 中的数据将相同。

$idp=$_POST['id_patient'];
$dt=$_POST['date'];
$tm=$_POST['time'];
$dn=$_POST['doctor_name'];

$query = "INSERT INTO doctor1 (doctor_name, id_patient, date, time) 
            values ('$dn', '$idp', '$dt', '$tm')"; 

$result = @mysql_query($query) or die("REPORT Failed to save data.");

$last_insert_no_que = mysql_insert_id();

@query2 = "INSERT INTO status_queue (id_patient, doctor_name, no_que, date, time) 
            values ('$idp', '$dn', '$last_insert_no_que', '$dt', '$tm')"; 


$result = @mysql_query($query2) or die("REPORT Failed to save data.");

但该代码不起作用

Answer 1

有用 ！我只需要删除“@”运算符.. :) ~ thx you

所以这是我的代码：

$idp=$_POST['id_patient'];
$dt=$_POST['date'];
$tm=$_POST['time'];
$dn=$_POST['doctor_name'];

$query = "INSERT INTO doctor1 (doctor_name, id_patient, date, time) 
            values ('$dn', '$idp', '$dt', '$tm')"; 

$result = mysql_query($query) or die(mysql_error());

$last_insert_no_que = mysql_insert_id();

$query2 = "INSERT INTO status_queue (id_patient, doctor_name, no_que, date, time) 
            values ('$idp', '$dn', '$last_insert_no_que', '$dt', '$tm')"; 


$result = mysql_query($query2) or die(mysql_error());

>