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正如我在标题中提到的那样，我正在“bid_userloc”表中请求纬度和经度……但我需要结合“wp_usermeta”表中的信息……

SET @centerLat = '48.531157';
SET @centerLng = '-123.782959';

SELECT *, ( 3959 * acos( cos( radians( @centerLat ) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(@centerLng) ) + sin( radians( @centerLat ) ) * sin( radians( lat ) ) ) ) AS distance FROM bid_userloc HAVING distance < 25 ORDER BY distance LIMIT 0 , 20

并使用user_id来自 的SELECT *，我需要从wp_userdata表中获取一些用户数据，如下所示：

id
meta_key
meta_value

例如，我需要meta_value“meta_key昵称”......以及其他一些，但是一旦我看到它是如何完成的，我可以添加更多。

对此，我真的非常感激！

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2 回答 2

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试试这个，用你原来的距离代替距离，用真实的东西代替其他东西：

SET @centerLat = '48.531157';
SET @centerLng = '-123.782959';

SELECT bid_userloc.*, distance, nickname.meta_value, something_else.meta_value
FROM bid_userloc
LEFT JOIN wp_usermeta AS nickname 
    ON nickname.userid = bid_userloc.user_id 
        AND nickname.meta_key = 'nickname'
LEFT JOIN wp_usermeta AS something_else 
    ON something_else.userid = bid_userloc.user_id 
        AND something_else.meta_key = 'something_else'
HAVING distance < 25
ORDER BY distance 
LIMIT 0 , 20
于 2012-10-20T00:17:09.257 回答
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修改后的答案如下：

SET @centerLat = '48.531157';
SET @centerLng = '-123.782959';

SELECT bid_userloc.*, nickname.meta_value, last_name.meta_value,
( 3959 * acos( cos( radians( @centerLat ) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(@centerLng) ) + sin( radians( @centerLat ) ) * sin( radians( lat ) ) ) ) AS distance
FROM bid_userloc
LEFT JOIN wp_usermeta AS nickname 
    ON nickname.user_id = bid_userloc.user_id 
        AND nickname.meta_key = 'nickname'
LEFT JOIN wp_usermeta AS last_name 
    ON last_name.user_id = bid_userloc.user_id 
        AND last_name.meta_key = 'last_name'
HAVING distance < 25
LIMIT 0 , 20
于 2012-10-20T00:52:42.477 回答