1

我的查询返回一个看起来像这样的表（请注意，我发布了一个非常简化的输出版本）：

+-------+------+------+------+------+
|       |  1   |  2   |  3   |  4   |
+-------+------+------+------+------+
| 14234 | 3    | null | null | null |
| 14234 | null | null | 32   | null |
| 33334 | 4    | null | null | 5    |
| 33334 | null | 3    | null | null |
+-------+------+------+------+------+

我想重新格式化它看起来像这样：

+-------+---+------+------+------+
|       | 1 |  2   |  3   |  4   |
+-------+---+------+------+------+
| 14234 | 3 | null | 32   | null |
| 33334 | 4 | 3    | null | 5    |
+-------+---+------+------+------+

正如您所看到的，这些行已经放在一起（压缩），我不知道正确的术语是什么。

有没有一种快速的方法可以用 sql server 做到这一点？

这是原始查询：

;WITH 
PivotQuery as (
    select client_id,
       [1],[2],[3],[4],[5],[6],[7]
       from
       (   SELECT DISTINCT CLIENT_ID
       , PATIENT_ID
       , count(*) over (partition by client_id, patient_id) AS patientcount

       from f_accession_daily) as SourceTable
       PIVOT
       (
       count(patient_id)
       for patientcount in ([1],[2],[3],[4],[5],[6],[7])
       ) as pivottable),

MinMaxTimes as (
    SELECT a.client_id AS client_id
    ,a.patientcount TimesTested
       , count(a.patientcount)/a.patientcount AS count
       , max(f.received_date) AS maxRecDate
       , min(f.received_date) AS minRecDate
    FROM
    (
       SELECT DISTINCT CLIENT_ID
       , PATIENT_ID
       , count(*) over (partition by client_id, patient_id) AS patientcount

       from f_accession_daily

    ) AS a
    JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
       AND a.PATIENT_ID = f.PATIENT_ID

    GROUP BY a.CLIENT_ID, a.patientcount),

maxDates as (
SELECT client_id, [1] maxdate1, [2] maxdate2, [3] maxdate3, [4] maxdate4, [5] maxdate5, [6] maxdate6, [7] maxdate7
FROM MinMaxTimes t
PIVOT (max(maxRecDate)
for TimesTested IN ([1], [2], [3], [4], [5], [6], [7])
) as p),

minDates as (
SELECT client_id, [1] mindate1, [2] mindate2, [3] mindate3, [4] mindate4, [5] mindate5, [6] mindate6, [7] mindate7
FROM MinMaxTimes t
PIVOT (max(minRecDate)
for TimesTested IN ([1], [2], [3], [4], [5], [6], [7])
) as p)

SELECT i.client_id, 
    p.[1], maxdate1, mindate1, 
    p.[2], maxdate2, mindate2, 
    p.[3], maxdate3, mindate3, 
    p.[4], maxdate4, mindate4, 
    p.[5], maxdate5, mindate5, 
    p.[6], maxdate6, mindate6, 
    p.[7], maxdate7, mindate7   
FROM PivotQuery p
LEFT OUTER JOIN maxDates a ON p.client_id = a.client_id
LEFT OUTER JOIN mindates i ON a.client_id = i.client_id
4

1 回答 1

4

我将您的示例数据中的第一列称为“fk”

SELECT fk,MAX(Col1),MAX(Col2),MAX(Col3),MAX(Col4)
FROM dbo.YourTable
GROUP BY fk

此查询聚合 fk 列上的行。如果您有不止一行具有相同的 fk 值并且在 MAX() 列之一中具有 NOT NULL 值，则将选择最大值。请改用 SUM() 来计算总和。两者都将忽略 NULL 值。但是，也会有关于这一事实的警告。

于 2012-10-19T21:02:37.700 回答