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我的 Android 应用程序中的搜索功能有效。我正在使用onSearchRequested()；调用搜索功能。现在我想做的是不使用onSearchRequested()；并将字符串从 an 传递EditText给 search 方法并在 List 中显示结果。这是我的搜索，因为它在onSearchRequested被调用时起作用：

SearchPage活动：

    DBHelper = new DBAdapter(this);
    DBHelper.open();
    Intent intent = getIntent();

    if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
        String query = intent.getStringExtra(SearchManager.QUERY);
        showResults(query);

    }
    //--- END onSearchRequested


private void showResults(String query) {
    Cursor cursor = DBHelper.searchDB(query);
    startManagingCursor(cursor);
    String[] searchFrom = new String[] { DBAdapter.KEY_YEAR,
            DBAdapter.KEY_MAKE, DBAdapter.KEY_MODEL };
    int[] displayHere = new int[] { R.id.rYearTV, R.id.rMakeTV,
            R.id.rModelTV };

    final SimpleCursorAdapter records = new SimpleCursorAdapter(this,
            R.layout.record_2, cursor, searchFrom, displayHere);

    setListAdapter(records);

DBAdapter活动：

//--- GET RECORDS FOR SEARCH
    public Cursor searchDB(String query) { 

    String[] parts = query.split(" "); 

    String queryString = ""; 
    for(int i = 0; i < parts.length; i++) { 
        queryString += KEY_YEAR + " LIKE '%" + parts[i] + "%' OR "; 
        queryString += KEY_MAKE + " LIKE '%" + parts[i] + "%' OR "; 
        queryString += KEY_MODEL + " LIKE '%" + parts[i] + "%'"; 
        if(i != (parts.length - 1)) { 
            queryString += " OR "; 
        } 
    } 

    return db.query(true, DB_TABLE,  
        new String[] { KEY_ROWID, KEY_SDATE, KEY_YEAR, KEY_MAKE, KEY_MODEL },  
        queryString, null, null, null, null, null); 
}
//--- END Get Records for Search

我想将一个字符串传递给搜索函数String searchData = searchEditText.getText().toString();，并让搜索函数通过按“搜索”按钮来处理传递的字符串。有人可以帮助我开始吗？

4

1 回答 1

1

你的布局中应该有EditText这样的：

       <EditText
            android:id="@+id/search_query"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:hint="search"
            android:imeOptions="actionSearch"
            android:inputType="text" />

在您的活动中onCreate：

EditText searchQuery = (EditText) findViewById(R.id.search_query);
searchQuery.setOnEditorActionListener(new OnEditorActionListener() {
            public boolean onEditorAction(TextView v, int actionId,
                    KeyEvent event) {
                if (actionId == EditorInfo.IME_ACTION_SEARCH) {
                    String searchData = searchQuery.getText().toString();
                            showResults(searchData); //passing string to search in your database to your method
                    return true;
                }
                return false;
            }
    });

setOnEditorActionListener用于在用户按下search键盘上的按钮时执行搜索。imeActions 您可以在此处阅读更多信息。

根据您的代码调用showResults(searchData);进行搜索并在列表中显示结果。

编辑： 根据您的代码在SearchPage活动中调用它：

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    //setContentView and other your features

    DBHelper = new DBAdapter(this);
    DBHelper.open();

    EditText searchQuery = (EditText) findViewById(R.id.search_query);

    Button yourButton = (Button) findViewById(R.id.yourButtonId);
    yourButton.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            String searchData = searchQuery.getText().toString();
            showResults(searchQuery);
        }
    });
}

private void showResults(String query) {
    Cursor cursor = DBHelper.searchDB(query);
    startManagingCursor(cursor);
    String[] searchFrom = new String[] { DBAdapter.KEY_YEAR,
            DBAdapter.KEY_MAKE, DBAdapter.KEY_MODEL };
    int[] displayHere = new int[] { R.id.rYearTV, R.id.rMakeTV,
            R.id.rModelTV };

    final SimpleCursorAdapter records = new SimpleCursorAdapter(this,
            R.layout.record_2, cursor, searchFrom, displayHere);

    setListAdapter(records);
}
于 2012-10-19T20:39:02.567 回答