1

我有一个看起来像这样的字符串:

"["xxx","yyy","zzz"]"

谁能给我一个关于如何将其转换为如下所示数组的提示:

somestring[0]="xxx"
somestring[1]="yyy"
somestring[2]="zzz"
4

3 回答 3

2

表达方式

"[\"xxx\",\"yyy\",\"zzz\"]".replaceAll( "[\\\"\\[\\]]", "" ).split( "," );

将产生一个数组:

a[0] = "xxx";
a[1] = "yyy";
a[2] = "zzz";

我希望...

[1小时后……]

我确定:

public static void main(String[] args) {
    for( String part : "[\"xxx\",\"yyy\",\"zzz\"]".replaceAll( "[\\\"\\[\\]]", "" ).split( "," )) {
        System.out.println( part );
    }
}

输出:

xxx
yyy
zzz
于 2012-10-19T17:13:42.603 回答
1

肮脏的黑客

String s1="[\"xxx\",\"yyy\",\"zzz\"]";
        String s2= s1.replaceAll("\"", "" );
        s2=s2.replace("[", "");
        s2=s2.replace("]", "");
        String ar[] =s2.split(",");
于 2012-10-19T18:10:22.083 回答
0

查看输入字符串模式,substring也可以:

String inStr = "\"[\"xxx\",\"yyy\",\"zzz\"]\"";
String [] inArray = inStr.substring(0,inStr.length()-2).substring(2).split(",");
System.out.println(Arrays.toString(inArray));

将打印:

    ["xxx", "yyy", "zzz"]

如果您想删除引号 ("),请编写如下:

String inStr = "\"[\"xxx\",\"yyy\",\"zzz\"]\"";
String [] inArray1 = inStr.substring(0,inStr1.length()-2)
                          .substring(2).replaceAll("\"","").split(",");
System.out.println(Arrays.toString(inArray1));

或者你可以这样做:

String inStr = "\"[\"xxx\",\"yyy\",\"zzz\"]\"";
String [] inArray = inStr.replaceAll( "[\\\"\\[\\]\"]", "").split( "," );
System.out.println(Arrays.toString(inArray0));

以上两个将打印:

    [xxx, yyy, zzz]
于 2012-10-19T17:19:36.067 回答