1

在我的 NotifyIcon 的 Ballon Tip 关闭后，图标仍留在托盘中。只有当我用鼠标光标悬停它时它才会消失。

我有一个类 Notification.cs，它有一个组件 - NotifyIcon。

我从我的控制台应用程序中调用它，因为我只想在满足某些条件时显示通知。

一些代码：

  • 我如何从我的程序中调用通知：

    Notification not = new Notification("Error occured, do this or that", "Some error", System.Windows.Forms.ToolTipIcon.Error);
not.getIcon().ShowBalloonTip(1000);

  • 通知类：

    public Notification(string baloonTipText, string baloonTipTitle, System.Windows.Forms.ToolTipIcon icon) : this()
{
    this.icon.Visible = true;
    this.icon.BalloonTipText = baloonTipText;
    this.icon.BalloonTipTitle = baloonTipTitle;
    this.icon.BalloonTipIcon = icon;
}

public System.Windows.Forms.NotifyIcon getIcon()
{
    return this.icon;
}

private void icon_BalloonTipClosed(object sender, EventArgs e)
{
    this.icon.Visible = false;
    this.icon.Dispose();            
}

有任何想法吗？

4

2 回答 2

3

因为您在控制台应用程序中运行，所以icon_BalloonTipClosed当气球提示关闭时不会调用您的处理程序（无消息泵）。您需要Dispose在应用程序退出时手动调用或设置一个超时时间长于气球提示超时时间的计时器（System.Threading.Timer,System.Windows.Forms.Timer将不起作用）。例如：

timer = new Timer(state => not.getIcon().Dispose(), null, 1200, Timeout.Infinite);
于 2012-10-19T14:30:24.223 回答
0 
using System;
using System.ComponentModel;
using System.Drawing;
using System.IO;
using System.Reflection;
using System.Windows.Forms;

namespace ShowToolTip
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void btBallonToolTip_Click(object sender, EventArgs e)
        {
            ShowBalloonTip();
            this.Hide();
        }

        private void ShowBalloonTip()
        {
            Container bpcomponents = new Container();
            ContextMenu contextMenu1 = new ContextMenu();

            MenuItem runMenu = new MenuItem();
            runMenu.Index = 1;
            runMenu.Text = "Run...";
            runMenu.Click += new EventHandler(runMenu_Click);

            MenuItem breakMenu = new MenuItem();
            breakMenu.Index = 2;
            breakMenu.Text = "-------------";

            MenuItem exitMenu = new MenuItem();
            exitMenu.Index = 3;
            exitMenu.Text = "E&xit";

            exitMenu.Click += new EventHandler(exitMenu_Click);

            // Initialize contextMenu1
            contextMenu1.MenuItems.AddRange(
                        new System.Windows.Forms.MenuItem[] { runMenu, breakMenu, exitMenu });

            // Initialize menuItem1

            this.ClientSize = new System.Drawing.Size(0, 0);
            this.Text = "Ballon Tootip Example";

            // Create the NotifyIcon.
            NotifyIcon notifyIcon = new NotifyIcon(bpcomponents);

            // The Icon property sets the icon that will appear
            // in the systray for this application.
            string iconPath = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location) + @"\setup-icon.ico";
            notifyIcon.Icon = new Icon(iconPath);

            // The ContextMenu property sets the menu that will
            // appear when the systray icon is right clicked.
            notifyIcon.ContextMenu = contextMenu1;

            notifyIcon.Visible = true;

            // The Text property sets the text that will be displayed,
            // in a tooltip, when the mouse hovers over the systray icon.
            notifyIcon.Text = "Morgan Tech Space BallonTip Running...";
            notifyIcon.BalloonTipText = "Morgan Tech Space BallonTip Running...";
            notifyIcon.BalloonTipTitle = "Morgan Tech Space";
            notifyIcon.ShowBalloonTip(1000);
        }

        void exitMenu_Click(object sender, EventArgs e)
        {
            this.Close();
        }

        void runMenu_Click(object sender, EventArgs e)
        {
            MessageBox.Show("BallonTip is Running....");
        }
    }
}
于 2013-09-11T08:51:54.757 回答