0

我有一个工作查询，它​​给了我最大日期：

SELECT a.client_id AS client_id
   , a.patientcount AS patientcount
   , received_date AS maxRecDate
FROM
(
   SELECT DISTINCT CLIENT_ID
   , PATIENT_ID
   , count(*) over (partition by client_id, patient_id) AS patientcount
   from f_accession_daily
) AS a
JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
   AND a.PATIENT_ID = f.PATIENT_ID
GROUP BY f.RECEIVED_DATE, a.CLIENT_ID, a.patientcount
HAVING f.RECEIVED_DATE = MAX(f.received_date)

在同一个查询中，我还想返回 min(f.received_date)。

有没有办法做到这一点？也许与子查询？

4

2 回答 2

2

我可能遗漏了一些东西，但我不明白你为什么要分组f.RECEIVED_DATE

我认为查询可能是：

SELECT a.client_id AS client_id
   , a.patientcount AS patientcount
   , max(f.received_date) AS maxRecDate
   , min(f.received_date) AS minRecDate
FROM
(
   SELECT DISTINCT CLIENT_ID
   , PATIENT_ID
   , count(*) over (partition by client_id, patient_id) AS patientcount
   from f_accession_daily
) AS a
JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
   AND a.PATIENT_ID = f.PATIENT_ID
GROUP BY a.CLIENT_ID, a.patientcount

我没有对此进行测试，但我认为它应该可以工作。

于 2012-10-19T06:00:11.593 回答
1

在您的查询中，添加一个 OR 条件以检查 MIN 日期。解决问题

SELECT a.client_id AS client_id
, a.patientcount AS patientcount
, received_date AS maxRecDate
FROM
(
SELECT DISTINCT CLIENT_ID
, PATIENT_ID
, count(*) over (partition by client_id, patient_id) AS patientcount
from f_accession_daily
) AS a
JOIN F_ACCESSION_DAILY AS f ON a.CLIENT_ID = f.CLIENT_ID
AND a.PATIENT_ID = f.PATIENT_ID
GROUP BY f.RECEIVED_DATE, a.CLIENT_ID, a.patientcount
HAVING f.RECEIVED_DATE = MAX(f.received_date) 
OR f.RECEIVED_DATE = MIN(f.received_date) -- Newly added condition
于 2012-10-19T08:53:40.527 回答