0

假设我有以下代码:

public Stack s1;
public Stack s2;

//I want to take the top element from s1 and push it onto s2

s1.pop();

//Gather recently popped element and assign it a name.

s2.push(recentlyPopped);

关于我将如何做到这一点的任何想法?谢谢。

4

3 回答 3

3

基本形式是

s2.push(s1.pop());

如果您需要在将数据推入第二个堆栈之前/之后处理来自第一个堆栈的数据,您可以使用

YourClass yourClass = s1.pop();
//process yourClass variable...
s2.push(yourClass);
//more process to yourClass variable...

请记住在使用该方法之前检查 s1 是否为空,pop否则您可能会收到 EmptyStackException。

if (!s1.isEmpty()) {
    s2.push(s1.pop());
}
于 2012-10-19T03:01:45.907 回答
1

尝试

String[] inputs = { "A", "B", "C", "D", "E" };
Stack<String> stack1 = new Stack<String>();
Stack<String> stack2 = new Stack<String>();
for (String input : inputs) {
  stack1.push(input);
}
System.out.println("stack1: " + stack1);
System.out.println("stack2: " + stack2);
stack2.push(stack1.pop());
System.out.println("stack1: " + stack1);
System.out.println("stack2: " + stack2);

输出将是:

stack1: [A, B, C, D, E]
stack2: []
stack1: [A, B, C, D]
stack2: [E]
于 2012-10-19T03:15:03.513 回答
0

除非您有其他未在问题中指定的约束。一种方法是:

YourElementType elem = s1.pop();

s2.push(elem);
于 2012-10-19T03:02:33.750 回答