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我有一个带有文本框的gridview

我想在按钮单击时获取此文本框的值

但我总是收到“0”（默认）值

我认为这个问题与视图状态有关，但我不确定

请告诉我我做错了什么？

源代码：

protected void Page_Load(object sender, EventArgs e)
{
    DataSet dataSet = new DataSet("MyDataSet");
    DataTable table = new DataTable();
    table.Columns.Add(new DataColumn("NameValue"));
    table.Columns.Add(new DataColumn("Number"));
    table.Columns.Add(new DataColumn("NumberValue"));
    dataSet.Tables.Add(table);

    DataRow row = dataSet.Tables[0].NewRow();
    row[0] = "Name";
    row[1] = "0";

    dataSet.Tables[0].Rows.Add(row);

    this.MyGridView.DataSource = dataSet;
    this.MyGridView.DataBind();
}

protected void Button1_Click(object sender, EventArgs e)
{
    TextBox txtsn = ((TextBox)this.MyGridView.Rows[0].FindControl("NumberTextBox"));
    string sn = txtsn.Text;
}




<body>
    <form id="form1" runat="server">
    <div>
        <asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />
        <asp:GridView ID="MyGridView" AutoGenerateColumns="false" ShowHeader="false" runat="server" >
            <Columns>
                <asp:TemplateField>
                    <ItemTemplate>
                        <asp:Label ID="NameLabel" runat="server" Text='<%#Eval("NameValue")%>' />
                    </ItemTemplate>
                </asp:TemplateField>
                <asp:TemplateField>
                    <ItemTemplate>
                        <asp:TextBox ID="NumberTextBox" runat="server" Text='<%#Eval("NumberValue")%>' />
                    </ItemTemplate>
                </asp:TemplateField>
            </Columns>
        </asp:GridView>
    </div>
    </form>
</body>
4

2 回答 2

2

问题是您总是将网格绑定到它，DataSource即使在回发时也是如此。这会覆盖用户所做的所有更改。

而是使用该IsPostBack 属性：

protected void Page_Load(object sender, EventArgs e)
{
    if(!IsPostback)
    {
        DataSet dataSet = new DataSet("MyDataSet");
        DataTable table = new DataTable();
        table.Columns.Add(new DataColumn("NameValue"));
        table.Columns.Add(new DataColumn("Number"));
        table.Columns.Add(new DataColumn("NumberValue"));
        dataSet.Tables.Add(table);

        DataRow row = dataSet.Tables[0].NewRow();
        row[0] = "Name";
        row[1] = "0";

        dataSet.Tables[0].Rows.Add(row);

        this.MyGridView.DataSource = dataSet;
        this.MyGridView.DataBind();
    }
}

只有在某些内容发生更改时才需要重新加载DataSource（删除或添加记录，用户单击排序列或您有分页）。但是你应该只在适当的事件处理程序中而不是在 page_load 中这样做。因此，最好将此代码包装在可以从任何地方调用的方法中。

于 2012-10-18T15:22:22.473 回答
1

You're data binding your grid on postbacks, which is causing this issue. You want to check to see if the request is a post:

protected void Page_Load(object sender, EventArgs e)
{
    if (!IsPostback)
    {
        DataSet dataSet = new DataSet("MyDataSet");
        DataTable table = new DataTable();
        table.Columns.Add(new DataColumn("NameValue"));
        table.Columns.Add(new DataColumn("Number"));
        table.Columns.Add(new DataColumn("NumberValue"));
        dataSet.Tables.Add(table);

        DataRow row = dataSet.Tables[0].NewRow();
        row[0] = "Name";
        row[1] = "0";

        dataSet.Tables[0].Rows.Add(row);

        this.MyGridView.DataSource = dataSet;
        this.MyGridView.DataBind();
    }
}
于 2012-10-18T15:23:48.043 回答