sql - 如何在sql中对特定列表进行排序

Question

嗨，我正在使用此查询来制作事件列表

SELECT *, CASE
WHEN ((month > 9 OR (month =9 and days >= 22)) AND year <= 2012)then 'list1'
WHEN (year <= 2013) then 'list2' 
WHEN (year > 2013)then 'list3' 
end as sortlist from events order by sortlist, date

现在我想按相同的 sql 对 list3 进行排序，按年份排序。这可能吗？

Answer 1

如果你有 SQL SERVER 2005 或更高版本，你可以这样做

SELECT
    *,
    CALC.sortlist
from events as e
    outer apply
    (
        select
                case
                WHEN ((e.month > 9 OR (e.month =9 and e.days >= 22)) AND e.year <= 2012)then 'list1'
                WHEN (e.year <= 2013) then 'list2' 
                WHEN (e.year > 2013)then 'list3' 
            end as sortlist
    ) as CALC
order by
    CALC.sortlist, CALC.date,
    case when CALC.sortlist = 'list3' then e.year else null end

你也可以这样做，但如果你的情况等于'list3'，它并不完全按年份排序（我的意思是如果你要改变表达式，case你也需要改变order by）

SELECT
    *,
    case
        WHEN ((e.month > 9 OR (e.month =9 and e.days >= 22)) AND e.year <= 2012)then 'list1'
        WHEN (e.year <= 2013) then 'list2' 
        WHEN (e.year > 2013)then 'list3' 
    end as sortlist
from events as e
order by
    sortlist, e.date,
    case when e.year > 2013 then e.year else null end

Answer 2

我得到了解决方案。为了按顺序，我刚刚编辑为

 order by sortlist, case when sortlist='list3' then year else null end,