sql - MySQL，获取用户排名

Question

我有一个如下的mysql表：

id     name     points
1      john     4635
3      tom      7364
4      bob      234
6      harry    9857

我基本上想在不选择所有用户的情况下获得单个用户排名。我只想通过 id 选择一个用户并获得由他们拥有的点数决定的用户排名。

例如，通过 id 3 选择排名 2 的 tom。

干杯

伊夫

Answer 1

SELECT  uo.*, 
        (
        SELECT  COUNT(*)
        FROM    users ui
        WHERE   (ui.points, ui.id) >= (uo.points, uo.id)
        ) AS rank
FROM    users uo
WHERE   id = @id

密集排名：

SELECT  uo.*, 
        (
        SELECT  COUNT(DISTINCT ui.points)
        FROM    users ui
        WHERE   ui.points >= uo.points
        ) AS rank
FROM    users uo
WHERE   id = @id

Answer 2

如果出现关系，@Quassnoi 的解决方案将失败。以下是适用于平局的解决方案：

SELECT *,
IF (@score=ui.points, @rank:=@rank, @rank:=@rank+1) rank,
@score:=ui.points score
FROM users ui,
(SELECT @score:=0, @rank:=0) r
ORDER BY points DESC

Answer 3

 SET @rownum := 0;
 SELECT rank, score FROM ( SELECT @rownum := @rownum +1 AS rank, `score` ,`user_id`
 FROM leaderboard 
 ORDER BY  `score` DESC , `updated_timestamp` ) as result WHERE `user_id`=$user_id
 LIMIT 1