你的假设是错误的;您的派生类的构造函数可以具有任何签名,只要它们使用 MyBase.New 正确调用其基类的构造函数之一。这是一个完整的例子:
Imports System
Public Class MainClass
Shared Sub Main()
Dim w As New Window(5, 10)
w.DrawWindow( )
Dim lb As New ListBox(20, 30, "Hello world")
lb.DrawWindow( )
End Sub
End Class
Public Class Window
Public Sub New(ByVal top As Integer, ByVal left As Integer)
Me.top = top
Me.left = left
End Sub 'New
Public Sub DrawWindow( )
Console.WriteLine("Drawing Window at {0}, {1}", top, left)
End Sub
Private top As Integer
Private left As Integer
End Class
Public Class ListBox
Inherits Window
Public Sub New(ByVal top As Integer, ByVal left As Integer, ByVal theContents As String)
MyBase.New(top, left) '
mListBoxContents = theContents
End Sub
Public Shadows Sub DrawWindow( )
MyBase.DrawWindow( )
Console.WriteLine("Writing string to the listbox: {0}", mListBoxContents)
End Sub
Private mListBoxContents As String
End Class
编辑:您根本不需要保留或扩展基类构造函数的签名。这是有效的,例如:
Public Class ListBox
Inherits Window
Public Sub New(ByVal theContents As String)
MyBase.New(20, 30) '
mListBoxContents = theContents
End Sub
'More code
End Class