在 SQL Server中存储System.Version的最佳方式是什么？
当我使用 varchar 类型时，按 asc 排序的结果是：
1.0.0.0
11.0.0.0
12.0.0.0
2.0.0.0
问问题
5763 次
3 回答
11
您可以使用 varchar 列
你可以这样订购
SELECT *
FROM t_version
ORDER BY CAST('/' + vid + '/' AS HIERARCHYID)
SQL fiddle 今天不工作，否则我可以展示一个演示
请运行它进行测试
SELECT * FROM
( VALUES
( '1.0.0.0' ),
( '11.0.0.0' ),
('12.0.0.0'),
('2.0.0.0') ) AS vid ( vid )
ORDER BY CAST('/' + vid + '/' AS HIERARCHYID)
于 2012-10-17T11:58:28.370 回答
7
只需将其存储为普通 varchar，这对于使用 PARSENAME 将字符串和顺序拆分为 4 个单独列的最多 4 个部分的版本非常有用。
IE
ORDER BY PARSENAME(version,4),
PARSENAME(version,3),
PARSENAME(version,2),
PARSENAME(version,1)
于 2012-10-17T11:58:46.483 回答
0
为了支持混合长度版本之间的排序（例如“1.2”与“1.2.3.4”），可以执行到小数的映射（作为内联表值函数）。
create function Common.ufn_OrderableVersion(@pVersion nvarchar(100))
returns table
as
/*---------------------------------------------------------------------------------------------------------------------
Purpose: Provide a mapping from Versions of the form 'a.b.c.d', 'a.b.c, 'a.b', 'a', null to
an orderable decimal(25, 0)
Since Parsename() doesn't apply easily to mixed length comparisions (1.2 vs 1.2.3.4)
Test Cases:
select * from Common.ufn_OrderableVersion(null); -- null
select * from Common.ufn_OrderableVersion('0'); -- 1000000000000000000000000
select * from Common.ufn_OrderableVersion('1'); -- 1000001000000000000000000
select * from Common.ufn_OrderableVersion('1.2.3.4'); -- 1000001000002000003000004
select Version
from
(
select '1.3.5.3' as Version
union all
select '1.2.5.3' as Version
union all
select '1.1.5.3' as Version
union all
select '1.3.5.2' as Version
union all
select null as Version
union all
select '' as Version
union all
select '2' as Version
union all
select '1.2' as Version
union all
select '1' as Version
) v
order by (select Value from Common.ufn_OrderableVersion(Version))
Modified By Description
---------- -------------- ---------------------------------------------------------------------------------------
2015.08.24 crokusek Initial Version
---------------------------------------------------------------------------------------------------------------------*/
return
-- 25 = 1 + VersionPositions * MaxDigitsPerSegment
select convert(decimal(25,0), '1' +
stuff((select format(Value, '000000')
from
(
select convert(int, Value) as Value, RowNumber
-- Support empty string and partial versions. Null maps to null
from Common.ufn_SplitUsingXml(@pVersion + '.0.0.0.0', '.') -- pad right
where RowNumber <= 4 -- trim right
) as v
order by RowNumber
for xml path ('')
), 1, 0, '')
) as Value
go
依赖：
create function Common.ufn_SplitUsingXml
(
@pList nvarchar(max),
@pDelimiter nvarchar(255)
)
returns table
as
/*---------------------------------------------------------------------------------------------------------------------
Purpose: Split an Identifier using XML as an inline table valued function.
Using the SQL Server CLR (C#) capability would be the most efficient way to support this.
Warnings: Will not work if the input contains special XML characters like '<', '>' or '&'.
Caller must add "option (maxrecursion 0)" for lists greater than 100 (it can't be added within the ufn)
Modified By Description
---------- -------------- ---------------------------------------------------------------------------------------
2015.08.24 inet http://sqlperformance.com/2012/07/t-sql-queries/split-strings
---------------------------------------------------------------------------------------------------------------------*/
return
(
select Value = y.i.value('(./text())[1]', 'nvarchar(4000)'),
row_number() over (order by (select null)) as RowNumber
from
(
select x = convert(XML, '<i>'
+ replace(@pList, @pDelimiter, '</i><i>')
+ '</i>').query('.')
) AS a cross apply x.nodes('i') AS y(i)
-- option (maxrecursion 0) must be added by caller for lists greater than 100
);
go
比较：
alter function Common.ufn_CompareVersions
(
@pVersionA nvarchar(100),
@pVersionB nvarchar(100)
)
returns table
as
/*---------------------------------------------------------------------------------------------------------------------
Purpose: Compare Version of the form 'A.B.C.D'.
Comparing versions of different lengths is also supported 'A.B'.
Test Cases:
select Result from Common.ufn_CompareVersions('1', null) -- 1
select Result from Common.ufn_CompareVersions(null, '1') -- -1
select Result from Common.ufn_CompareVersions('1', '1') -- 0
select Result from Common.ufn_CompareVersions('1', '2') -- -1
select Result from Common.ufn_CompareVersions('2', '1') -- 1
select Result from Common.ufn_CompareVersions('1', '1.2') -- -1
select Result from Common.ufn_CompareVersions('1.2', '1') -- 1
select Result from Common.ufn_CompareVersions('1.2.3.4', '1.2.3.4') -- 0
select Result from Common.ufn_CompareVersions('1.2.3', '1.2.3.4') -- -1
select Result from Common.ufn_CompareVersions('1.2.3.4', '1.2.3') -- 1
select Result from Common.ufn_CompareVersions('1.9.3.4', '1.2.3.4') -- 1
select Result from Common.ufn_CompareVersions('1.2.3.4', '1.9.3.4') -- -1
select Result from Common.ufn_CompareVersions('1.002', '1.2') -- 0
select Result from Common.ufn_CompareVersions('1.2', '1.2.0') -- 0
Modified By Description
---------- ----------- ------------------------------------------------------------------------------------------
2015.08.24 crokusek Initial Version
---------------------------------------------------------------------------------------------------------------------*/
return
with Compares as
(
select (select IsNull(Value, 0) from Common.ufn_OrderableVersion(@pVersionA)) as A,
(select IsNull(Value, 0) from Common.ufn_OrderableVersion(@pVersionB)) as B
)
select case when A > B then 1
when A < B then -1
else 0
end as Result
from Compares
go
于 2015-08-24T22:01:01.700 回答