0

我有两个表 第一个表:对于产品 第二个表:对于类别

我想像这样在浏览器中显示

类别1 (20) 类别2 (5) 类别3 (3)

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");
  $row_num_sub = mysql_num_rows($select_num_sub);
  $smarty->assign('numb',$row_num_sub);

 $sub_cats[] = $row_sub;
}
$smarty->assign('sub_cats',$sub_cats);
4

2 回答 2

0

尝试

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");         
 $sub_cats[] = $row_sub;
 $sub_cats['count']=mysql_num_rows($select_num_sub);
}
$smarty->assign('sub_cats',$sub_cats);

然后打电话给你的聪明人:

{$sub_cats.name} ({$sub_cats.count}) // $sub_cats.name 应该是类别的“名称”

于 2012-10-17T05:55:52.810 回答
0

尝试这个:

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");
  $smarty->assign('numb',$row_num_sub);

 $sub_cats[] = $row_sub;
 $sub_cats['count']=mysql_num_rows($select_num_sub);
}
$smarty->assign('sub_cats',$sub_cats);
于 2012-10-17T04:51:29.540 回答