如果用户允许出现在页面中，我有一个名为“验证”的提交类型按钮。验证按钮将 db 中的一行设置为已验证 (TRUE)
如果验证字段为真或假，我首先在 db 中检查。
如果 false 和 isset($_POST['valid']) 我显示按钮
<input <?php echo $disabledvalid; ?> type="submit" class="sub" name="valid" id="valid" value = "validate" />
在我输入将验证字段从 FALSE 更改为 true 的 UPDATE 查询之后。
当页面被处理时，if 被忽略并被执行更新查询？
我该如何解决这个问题？
<form action="view_support.php" method="post">
<?php
//check if validated field is true or false
$queryvalid = "SELECT validated FROM support WHERE suppid = $suppid";
$risqueryvalid = pg_query($queryvalid);
$row = pg_fetch_array($risqueryvalid);
$suppvalidated = $row['validated'];
//echo "supp " . $suppvalidated;
//$suppvalidated == "f";
unset($_POST['valid']);
//if validated field is false show me validate button
if ( $suppvalidated == FALSE && (isset($_POST['valid']) ){
$suppvalidated = 'true';
<input <?php echo $disabledvalid; ?> type="submit" class="sub" name="valid" id="valid" value = "validate" />
<?php
if(isset($_POST['valid'])){
$vquery = "UPDATE support SET validated = $suppvalidated WHERE suppid = $suppid";
$risvquery = pg_query($vquery);
if (!$risvquery) {
#die("Error during insert support");
die("Errore nella query $risvquery: " . pg_last_error());
}
unset($_POST['valid']);
}