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我有一个包含“客户”信息的数据库设置。我有一个 PHP 表单来搜索字符串、名字 (fname)、姓氏 (lname) 和电话号码 (phone)。出于某种原因，我什至没有让助手显示这些功能正在运行？我一遍又一遍地重新阅读这段代码，似乎无法弄清楚我在哪里遗漏了一些东西。

<form name="search" method="post" action="<?=$PHP_SELF?>">
 Seach for: <input type="text" name="find" /> in 
 <Select NAME="field">
 <Option VALUE="fname">First Name</option>
 <Option VALUE="lname">Last Name</option>
 <Option VALUE="phone">Phone #</option>
 </Select>
 <input type="hidden" name="searching" value="yes" />
 <input type="submit" name="search" value="Search" />
 </form>
 <? 
 //This is only displayed if they have submitted the form 
 if ($searching =="yes") 
 { 
 echo "<h2>Results</h2><p>"; 

 //If they did not enter a search term we give them an error 
 if ($find == "") 
 { 
 echo "<p>You forgot to enter a search term"; 
 exit; 
 } 

 // We preform a bit of filtering 
 $find = strtoupper($find); 
 $find = strip_tags($find); 
 $find = trim ($find); 

 //Now we search for our search term, in the field the user specified 
 $data = mysql_query("SELECT * FROM customer WHERE upper($field) LIKE'%$find%'"); 

 //And we display the results 
 while($result = mysql_fetch_array( $data )) 
 { 
 echo $result['fname']; 
 echo " "; 
 echo $result['lname']; 
 echo "<br>"; 
 echo $result['phone']; 
 echo "<br>"; 
 echo "<br>"; 
 } 

 //This counts the number or results - and if there wasn't any it gives them a little message explaining that 
 $anymatches=mysql_num_rows($data); 
 if ($anymatches == 0) 
 { 
 echo "Sorry, but we can not find an entry to match your query<br><br>"; 
 } 

 //And we remind them what they searched for 
 echo "<b>Searched For:</b> " .$find; 
 } 
 ?>
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2 回答 2

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您的脚本中有一些错误，我会尽力帮助您：

<? --> <?php

然后您的表单通过方法 POST 传递参数，因此您必须像这样检查搜索：

if ($_POST['searching'] =="yes")

你在这里有同样的错误：

if ($_POST['find'] == "")

和这里：

 $find = strtoupper($_POST['find']);

再见！

于 2012-10-16T13:33:20.713 回答
0

您应该首先创建一个如下所示的查询字符串，然后在mysql_queryHope this 中使用该字符串。

str = "SELECT * FROM customer WHERE upper(".$field.") LIKE'%".$find%."'";
于 2012-10-16T13:28:27.643 回答