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概述：
比较不同账户的农产品代理的日常交易，以发现代理和公司持股之间的差异，仅显示新产品；当前交易中的代码，但不是以前的交易。

目标：
按频率最高的代码（即苹果）对交易进行排序。

当前代码：

SELECT 
    Count(CurrentTrade.Code) AS CountOfCode, 
    CurrentTrade.portfolio_code, 
    CurrentTrade.Type, 
    CurrentTrade.Code, 
    sum(CurrentTrade.Custodian_holding) AS AgentHolding, 
    sum(CurrentTrade.Company_holding) AS CompanyHolding, 
    sum(CurrentTrade.Difference) AS TotalDifference
FROM 
    CurrentTrade 
    LEFT JOIN PrevTrade 
    ON CurrentTrade.Company_holding = PrevTrade.Company_holding
WHERE 
    PrevTrade.Company_holding) Is Null
GROUP BY CurrentTrade.Code, CurrentTrade.portfolio_code, CurrentTrade.Code, CurrentTrade.Type
ORDER BY count(CurrentTrade.Code);

当前结果：

 CountOfCode        account_code        Type        Code        AgentHodling        CompanyHolding        TotalDifference
 1                  acc001049        prod        mango        2500                  0        2500
 1                  acc636903        prod        mango        481081.29        481081.285        0.01
 1                  acc179186        prod        mango        453639.61        511285.81        -57646.2
 1                  acc179185        prod        mango        2775               2650        125
 1                  acc170001        prod        grapes       0                     1500        -1500
 1                  acc170000        prod        grapes       2500        0        2500
 1                  acc107104        prod        apple        49797.22        49797.28        -0.06
 1                  acc107103        prod        apple        0        -0.06        0.06
 1                  acc107102        prod        apple        2000        500        1500
 1                  acc107101        prod        apple        0        1500        -1500
 1                  acc001189        prod        apple        0        1090.513        -1090.513

参考：

我收到了一个答案（按计数排序不正确 - SQL（MS Access 2007）），所以这是一个跟进。

问题：

是否可以在不汇总所有结果的情况下按频率排序，并且仍然按最高频率（苹果、芒果、葡萄）显示订单，包括关联的帐号？
如果使用 sum 作为 order by，“不能在 ORDER BY 中具有聚合函数”，所以我不确定我是否可以这样做并且仍然保持帐号分开？

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1 回答 1

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将子句拉出ORDER BY到外层查询，内层查询会计算频率，如下：

SELECT * FROM (
SELECT 
    Count(CurrentTrade.Code) AS CountOfCode, 
    CurrentTrade.portfolio_code, 
    CurrentTrade.Type, 
    CurrentTrade.Code, 
    sum(CurrentTrade.Custodian_holding) AS AgentHolding, 
    sum(CurrentTrade.Company_holding) AS CompanyHolding, 
    sum(CurrentTrade.Difference) AS TotalDifference
FROM 
    CurrentTrade 
    LEFT JOIN PrevTrade 
    ON CurrentTrade.Company_holding = PrevTrade.Company_holding
WHERE 
    PrevTrade.Company_holding) Is Null
GROUP BY CurrentTrade.Code, CurrentTrade.portfolio_code, CurrentTrade.Code, CurrentTrade.Type
) ORDER BY CountOfCode ASC
于 2012-10-16T03:23:32.087 回答