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我正在尝试使用 HttpClient(HttpComponents) 制作 HttpPost。这是我的代码：

try{
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost post = new HttpPost(
                "https://accounts.google.com/o/oauth2/token");
            post.addHeader("accept", "application/json");
            post.addHeader("Content-Type", "application/json");

            List<NameValuePair> nvps = new ArrayList<NameValuePair>();
            nvps.add(new BasicNameValuePair("code", new String(code.getBytes(), Charset.forName("UTF-8"))));
            nvps.add(new BasicNameValuePair("client_id", "googleClientId"));
            nvps.add(new BasicNameValuePair("redirect_uri", "http://localhost:8080/myapp/test"));
            nvps.add(new BasicNameValuePair("client_secret", "ClientSecret"));
            nvps.add(new BasicNameValuePair("grant_type", "authorization_code"));
            post.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));


            HttpResponse resp = httpClient.execute(post);

            if (resp.getStatusLine().getStatusCode() != 200) {
                throw new RuntimeException("Failed : HTTP error code : "
                   + resp.getStatusLine().getStatusCode());
            }

            BufferedReader br = new BufferedReader(
                             new InputStreamReader((resp.getEntity().getContent())));

            String output;
            System.out.println("Output from Server .... \n");
            while ((output = br.readLine()) != null) {
                System.out.println(output);
                res = res + output;
            }
            System.out.println(output);
            httpClient.getConnectionManager().shutdown();
            } catch(Exception e){
                e.printStackTrace();
            }
            System.out.println(res);

我得到一个400代码。我怀疑这是因为我设置的所有参数都包含特殊字符，比如_ . and /它们被转义了。我怎样才能避免这种情况？还是我错过了真正的问题？

4

1 回答 1

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不应该是 http 标头“Content-Type”，application/x-www-form-urlencoded因为您对 post 参数进行了明确的 URL 编码？

于 2012-10-15T20:27:41.063 回答