给定以下两个表:
Person table
id (pk)
first
middle
last
age
Address table
id(pk)
person_id (fk person.id)
street
city
state
zip
如何创建返回邮政编码为 97229 的人员的所有信息的 SQL 语句?
给定以下两个表:
Person table
id (pk)
first
middle
last
age
Address table
id(pk)
person_id (fk person.id)
street
city
state
zip
如何创建返回邮政编码为 97229 的人员的所有信息的 SQL 语句?
Select * from people p, address a where p.id = a.person_id and a.zip='97229';
或者您必须尝试使用JOIN
哪种方法更有效、更好,因为 Gordon Linoff 在下面的评论中还说您需要学习这一点。
SELECT p.*, a.street, a.city FROM persons AS p
JOIN address AS a ON p.id = a.person_id
WHERE a.zip = '97299';
这 p.*
意味着它将显示 PERSONS 表的所有列。
您需要连接两个表:
select p.id, p.first, p.middle, p.last, p.age,
a.id as address_id, a.street, a.city, a.state, a.zip
from Person p inner join Address a on p.id = a.person_id
where a.zip = '97229';
这将从两个表中选择所有列。select
您当然可以通过在子句中选择不同的列来限制它。
像那样:
SELECT p.*, a.street, a.city FROM persons AS p
JOIN address AS a ON p.id = a.person_id
WHERE a.zip = '97299'
首先从人员表中选择所有记录,然后将所有这些记录与另一个表“地址”连接起来……现在你已经记录了所有在地址表中有地址的人……所以最后按邮政编码过滤你的记录。
select * from Person as P inner join Address as A on
P.id = A.person_id Where A.zip='97229'
select P.*,
A.Street,
A.City,
A.State
from Preson P
inner join Address A on P.id=A.Person_id
where A.Zip=97229
Order by A.Street,A.City,A.State