1

我正在开发一个 wpf 应用程序。我有一个这样的数据库。我有三列（id、name、profession）。listbox 显示名称列。当用户单击列表框中的项目时，我想在文本块中显示他/她的职业。列表框效果很好。我已将其绑定到数据视图。但是我如何在文本块中显示他/她的职业？

private void listBox1_SelectionChanged(object sender, SelectionChangedEventArgs e)

{

 //What can I write here?

}
4

2 回答 2

3

您应该只将 TextBlock 的文本属性绑定到列表框的选定项。 查看 MSDN 上的这篇文章。

 <StackPanel>
    <TextBlock Width="248" Height="24" Text="Colors:" 
        TextWrapping="Wrap"/>
    <ListBox x:Name="lbColor" Width="248" Height="56">
        <ListBoxItem Content="Blue"/>
        <ListBoxItem Content="Green"/>
        <ListBoxItem Content="Yellow"/>
        <ListBoxItem Content="Red"/>
        <ListBoxItem Content="Purple"/>
        <ListBoxItem Content="Orange"/>
    </ListBox>
    <TextBlock Width="248" Height="24" Text="You selected color:" />
    <TextBlock Width="248" Height="24">
        <TextBlock.Text>
            <Binding ElementName="lbColor" Path="SelectedItem.Content"/>
        </TextBlock.Text>
    </TextBlock>
</StackPanel>
于 2009-08-17T19:36:30.163 回答
0 
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Data;
using System.Data.OleDb;

namespace WpfApplication2
{
    /// <summary>
    /// Interaction logic for Window1.xaml
    /// </summary>
    public partial class Window1 : Window
    {
        public DataView view;
        public DataSet ds;
        public Window1()
        {

            InitializeComponent();
            BindData();


        }


        public void BindData() {

            OleDbConnection con = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=|DataDirectory|\\Information.mdb;Persist Security Info=True");
            con.Open();
            string sql = "Select * from Dictionary";
            OleDbCommand cmd = new OleDbCommand(sql, con);
            OleDbDataAdapter da = new OleDbDataAdapter(cmd);
            DataSet ds = new DataSet();
            try
            {

                da.Fill(ds, "Info");
                view = ds.Tables[0].DefaultView;
                listBox1.ItemsSource = view;


            }
            catch (Exception ex)
            { 




            }}

        private void textBox1_TextChanged(object sender, TextChangedEventArgs e)
            {

                view.RowFilter = string.Format("Name Like '{0}%'", textBox1.Text);

        }







    }
}




<Window x:Class="WpfApplication2.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="490">
    <Grid>
        <ListBox Margin="18,77,0,83" Name="listBox1" ItemsSource="{Binding Path=Name}" HorizontalAlignment="Left" Width="213" SelectionChanged="listBox1_SelectionChanged" >
            <ListBox.ItemTemplate>

                <DataTemplate>

                    <TextBlock Text="{Binding Path=Name}"> </TextBlock>
                </DataTemplate>



            </ListBox.ItemTemplate>
        </ListBox>

        <TextBox Height="23" Margin="18,40,0,0" Name="textBox1" VerticalAlignment="Top" TextChanged="textBox1_TextChanged" HorizontalAlignment="Left" Width="213" />
        <TextBlock HorizontalAlignment="Right"  Margin="0,77,42,83" Name="textBlock1" Width="185" Background="#FFE6C6C6" /><Label Height="28"  HorizontalAlignment="Right" Margin="0,39,76,0" Name="label1" VerticalAlignment="Top" Width="140">Label</Label>
    </Grid>
</Window>
于 2009-08-18T17:13:51.193 回答