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我正在尝试使用 sqlite 中的日期，我需要一种比较它们的方法。我的问题是，当我尝试将设置日期保存到数据库中时，它给了我新的值；然而，它们并没有太大区别——仅以毫秒为单位。

这是代码：

Date today = new Date();
today.setHours(0);
today.setMinutes(0);
today.setSeconds(0);

我如何让它给我恒定的价值？

PS我可以将它除以1000并保存，但我使用greenDao框架，它封装了插入逻辑。

谢谢。

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2 回答 2

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尝试：

Calendar now = Calendar.getInstance();
now.set(Calendar.HOUR, 0);
now.set(Calendar.MINUTE, 0);
now.set(Calendar.SECOND, 0);
now.set(Calendar.MILLISECOND, 0);

date = now.getTime();

new Date() 分配由 System.currentTimeMillis() 返回的当前时间。这意味着您不会在代码中重置毫秒。

于 2012-10-15T14:44:37.780 回答
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I think you might want to look at Java Date rounding

Basically the answers suggest using Apache commons-lang DataUtils. See http://commons.apache.org/lang/api-3.1/index.html and especially the truncate method:

public static Date truncate(Date date,int field)

Truncate this date, leaving the field specified as the most significant field.

For example, if you had the datetime of 28 Mar 2002 13:45:01.231, if

you passed with HOUR, it would return 28 Mar 2002 13:00:00.000. If this was passed with MONTH, it would return 1 Mar 2002 0:00:00.000.

于 2012-10-15T14:51:35.883 回答