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我正在编写一个使用线程池的客户端/服务器应用程序，以便多个客户端可以同时与服务器通信并向其发送命令：

但它不起作用，即使使用非常简单的客户端：

这是我的客户：

    if(args.length==0) {
        host="127.0.0.1";
        port=11111;
    } else {
        host=args[0];
        String portString = args[1];
        try {
            port = Integer.parseInt(portString);
        } catch(Exception e) {
            e.printStackTrace();
            port = 11111;
        }
    }

    try {
        System.out.println("Client connects to host=" + host + " port=" + port);
        Socket skt = new Socket(host, port);//line 30 in the exception
        BufferedReader myInput = new BufferedReader(new InputStreamReader(skt.getInputStream()));
        PrintWriter myOutput = new PrintWriter(skt.getOutputStream(), true);

        myOutput.println("Hello I am the Client!");
        String buf=myInput.readLine();
        System.out.println(buf + "=buf");


        if(buf!=null) {
            System.out.println("Client receives " + buf + " from the Server!");
            buf=myInput.readLine();
            System.out.println(buf);

        }
        myOutput.close();
        myInput.close();
        skt.close();

但我得到：

客户端连接到主机 = 127.0.0.1 端口 = 11111 java.net.ConnectException：连接被拒绝：在 java.net.DualStackPlainSocketImpl.socketConnect（未知来源）的 java.net.DualStackPlainSocketImpl.socketConnect（未知来源）的 java.net.DualStackPlainSocketImpl.connect0（本机方法）连接。 AbstractPlainSocketImpl.doConnect(Unknown Source) at java.net.AbstractPlainSocketImpl.connectToAddress(Unknown Source) at java.net.AbstractPlainSocketImpl.connect(Unknown Source) at java.net.PlainSocketImpl.connect(Unknown Source) at java.net.SocksSocketImpl。 connect(Unknown Source) at java.net.Socket.connect(Unknown Source) at java.net.Socket.connect(Unknown Source) at java.net.Socket.(Unknown Source) at java.net.Socket.(Unknown Source ) at client.Client.main(Client.java:30)//看代码处的注释

所以我认为我的服务器可能是错误的，因为我在客户端看不到它：

ServerMain.java

public static void main(String[] args) {

    try {
        clientlistener = new ClientListener(server);
        //serversocket = new ServerSocket();
    } catch (IOException e) {
        System.out.println("Could not listen on tcpPort: " + tcpPort);
        e.printStackTrace();
        System.exit(-1);
    } 
}

在这里，我用一个新的打开客户端监听器 

private static Server server = new Server();

并希望将其添加到 serverSocket 而不是 threadPool：

public ClientListener(Server server) throws ServerException{
    this.server=server;

     try {
            serverSocket = new ServerSocket(server.getTcpPort());
        } catch (IOException e) {
            throw new ServerException(e.getMessage());
        }

    System.out.println(String.format("Accepting new clients " +
            "on %s", serverSocket.getLocalSocketAddress()));
}

/**
 * Spawns new threads on incoming connection requests from clients.
 * */
@Override
public void run() {
    while(true){
        try {
            ClientCommunicator cc = new ClientCommunicator(serverSocket.accept(), pool);
            threadPool.execute(cc);
            clientComms.add(cc);
        } catch (SocketException e) {
            System.out.println(e.getMessage());
            return;
        } catch (IOException e) {
            System.out.println(e.getMessage());
            return;
        }
    }
}

ClientCommunicator 只是一个从命令行读取的类。

我的问题是：

我的套接字连接出了什么问题？

我打开一个并从客户那里接受它？

非常感谢你的回答！！！

4

1 回答 1

2

我认为您的服务器已关闭，这就是您收到拒绝连接的原因。我没有看到您的 server.accept() 调用使服务器套接字等待新客户端的到来并返回一个 Socket 对象而不是 SocketServer。

我已经为你完成了这段代码。我希望它有所帮助。

package com.sockets.exam1;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;

public class ServerCode {
    public static void main(String[] args) {
        try {
            ServerSocket server = new ServerSocket(11111);
            while (true) {                                              
                new ThreadSocket(server.accept());
            }
        } catch (Exception e) {
        }
    }
}
class ThreadSocket extends Thread{
    private Socket insocket;    
    ThreadSocket(Socket insocket){
        this.insocket = insocket;
        this.start();
    }       
    @Override
    public void run() {     
        try {
            System.out.println("procesing request");
            BufferedReader in = new BufferedReader(new InputStreamReader(
                    insocket.getInputStream()));
            PrintWriter out = new PrintWriter(insocket.getOutputStream(),
                    true);
            String instring = in.readLine();
            out.println("The server got this: " + instring.toUpperCase());
            insocket.close();
        } catch (IOException e) {
            e.printStackTrace();
        }       
    }
}
于 2012-10-13T19:33:05.370 回答