我得到了一个 python 2.7 脚本，它通过解决折叠几行仅按序列号更改的更一般问题来解决您的问题
import re
def do_compress(old_ints, ints):
"""
whether the ints of the current entry is the continuation of the previous
entry
returns a list of the indexes to compress, or [] or False when the current
line is not part of an indexed sequence
"""
return len(old_ints) == len(ints) and \
[i for o, n, i in zip(old_ints, ints, xrange(len(ints))) if n - o == 1]
def basic_format(file_start, file_stop):
return "[seq]{} .. {}".format(file_start, file_stop)
def compress(files, do_compress=do_compress, seq_format=basic_format):
p = None
old_ints = ()
old_indexes = ()
seq_and_files_list = []
# list of file names or dictionaries that represent sequences:
# {start, stop, start_f, stop_f}
for f in files:
ints = ()
indexes = ()
m = p is not None and p.match(f) # False, None, or a valid match
if m:
ints = [int(x) for x in m.groups()]
indexes = do_compress(old_ints, ints)
# state variations
if not indexes: # end of sequence or no current sequence
p = re.compile( \
'(\d+)'.join(re.escape(x) for x in re.split('\d+',f)) + '$')
m = p.match(f)
old_ints = [int(x) for x in m.groups()]
old_indexes = ()
seq_and_files_list.append(f)
elif indexes == old_indexes: # the sequence continues
seq_and_files_list[-1]['stop'] = old_ints = ints
seq_and_files_list[-1]['stop_f'] = f
old_indexes = indexes
elif old_indexes == (): # sequence started on previous filename
start_f = seq_and_files_list.pop()
s = {'start': old_ints, 'stop': ints, \
'start_f': start_f, 'stop_f': f}
seq_and_files_list.append(s)
old_ints = ints
old_indexes = indexes
else: # end of sequence, but still matches previous pattern
old_ints = ints
old_indexes = ()
seq_and_files_list.append(f)
return [ isinstance(f, dict) and seq_format(f['start_f'], f['stop_f']) or f
for f in seq_and_files_list ]
if __name__ == "__main__":
import sys
if len(sys.argv) == 1:
import os
lst = sorted(os.listdir('.'))
elif sys.argv[1] in ("-h", "--help"):
print """USAGE: {} [FILE ...]
compress the listing of the current directory, or the content of the files by
collapsing identical lines, except for a sequence number
"""
sys.exit(0)
else:
import string
lst = [string.rstrip(l, '\r\n') for f in sys.argv[1:] for l in open(f)])
for x in compress(lst):
print x
也就是说，在您的数据上：
bernard $ ./ls_sequence_compression.py given_data
[seq]filename_v003_0001.geo .. filename_v003_0007.geo
[seq]filename_v003_0032.geo .. filename_v003_0036.geo
[seq]testxxtest.0057.exr .. testxxtest.0063.exr
它基于与非数字文本匹配的两个连续行中存在的整数之间的差异。这允许在用作序列基础的字段更改时处理非统一输入...
这是一个输入示例：
01 - test8.txt
01 - test9.txt
01 - test10.txt
02 - test11.txt
02 - test12.txt
03 - test13.txt
04 - test13.txt
05 - test13.txt
06
07
08
09
10
这使：
[seq]01 - test8.txt .. 01 - test10.txt
[seq]02 - test11.txt .. 02 - test12.txt
[seq]03 - test13.txt .. 05 - test13.txt
[seq]06 .. 10
欢迎任何评论！
哈......我差点忘了：没有参数，这个脚本输出当前目录的折叠内容。