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MySQL 是否因为插入语句中的嵌套 SELECT 使用 COUNT(*) 函数而不是选择实际列而让我感到悲伤？那么，解决方法是什么？

这是故事：

mysql> explain test;
+----------+----------------------+------+-----+---------+-------+
| Field    | Type                 | Null | Key | Default | Extra |
+----------+----------------------+------+-----+---------+-------+
| language | varchar(50)          | YES  |     | NULL    |       |
| count    | smallint(5) unsigned | YES  |     | NULL    |       |
+----------+----------------------+------+-----+---------+-------+
2 rows in set (0.00 sec)

mysql> SELECT languages.name, COUNT(*) AS `total` FROM languages JOIN events ON languages.id     = events.language_id GROUP BY name HAVING total > 250 ORDER BY total DESC;
+-----------+-------+
| name      | total |
+-----------+-------+
| Spanish   | 60079 |
| Foochow   |  2838 |
| Mandarin  |  2396 |
| Russian   |  1675 |
| Arabic    |  1410 |
| Cantonese |  1358 |
| Korean    |   736 |
| French    |   531 |
| Punjabi   |   426 |
| Urdu      |   408 |
| Hebrew    |   276 |
| Pashto    |   255 |
+-----------+-------+
12 rows in set (0.00 sec)

mysql> INSERT INTO test (`language`,`count`) VALUES ((SELECT languages.`name`, COUNT(*) AS `total` FROM languages JOIN events ON languages.id = events.language_id GROUP BY name HAVING total > 250 ORDER BY total DESC));
ERROR 1136 (21S01): Column count doesn't match value count at row 1

谢谢。

4

2 回答 2

1

MySQL 不支持这种多列返回子查询，因此您看到的错误消息是因为该VALUES子句仅包含一个子查询，这强制（在某种意义上）只有一列。

要修复它，您可以跳过VALUES语法，只需编写：

INSERT
  INTO test (`language`,`count`)
SELECT languages.`name`, COUNT(*) AS `total`
  FROM languages
  JOIN events
    ON languages.id = events.language_id
 GROUP
    BY name
HAVING total > 250
 ORDER
    BY total DESC
;

（请参阅MySQL 5.6 参考手册中的第13.2.5.1 节“INSERT ... SELECT语法”。）

于 2012-10-12T20:40:43.220 回答
0

插入测试（`语言`，`计数`）

应该

INSERT INTO test (language,count)
于 2013-12-09T13:51:06.627 回答