php - 使用 PHP 从数据中提取 URL

Question

我有一些脚本可以从表格中提取一些文本并将其转储到我的文本文件中。我希望您的帮助只删除 URL，以便文本文件只显示 URL。

{
$result = @mysql_query("SELECT post_content_filtered FROM wp_posts ORDER BY post_date desc limit 200");
$tsv  = array();
$html = array();
while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $tsv[]  = implode("\t", $row);
    $html[] = "<tr><td>" .implode("</td><td>", $row) ."</td></tr>";
}

$tsv = implode("\r\n", $tsv);
$html = "<table>" . implode("\r\n", $html) . "</table>";
$fileName = 'finishedflippa.txt';
header("Content-type: application/vnd.ms-excel");
header("Content-Disposition: attachment; filename=$fileName");
echo $tsv;

post_content_filtered文本看起来像这样：

blahblahblah http://www.example.com blahblahblah
blahblahblah http://www.12345.com blahblahblah
blahblahblah http://www.gfds.com blahblahblah
blahblahblah http://www.45tyhju.com blahblahblah

blahblahblah每一行都是一样的。非常感谢。

Answer 1

URL有非常复杂的定义

你可以试试这个简单的匹配preg_match_all

$str = 'text looks something like this: 
blahblahblah http://www.example.com blahblahblah 
blahblahblah http://www.12345.com blahblahblah 
blahblahblah http://www.gfds.com blahblahblah 
blahblahblah http://www.45tyhju.com blahblahblah ' ;

preg_match_all('!https?://[\S]+!', $str, $matches);
var_dump($matches[0]);