1

我有一个表名为 JOB_Details ，数据显示如下：

 Employee_ID   Age          Department     Gender       
    001       30yrs          IT               M 
    002       34yrs          HR               F    
    003       39yrs          HR               F   
    004       49yrs          Finance          M        
    005       54yrs          IT               M 
    006       20yrs          HR               M 
    007       24yrs          HR               F   
    008       33yrs          Finance          F       
    009       29yrs          Finance          F        
    010       44yrs          IT               M

我希望显示的输出应该是

Age          Department:IT       Department:Finance  Department:HR    Total
             Male     Female     Male     Female     Male     Female
<30yrs         1         0         0         1         1         1       4
 30-34yrs      0         0         0         1         0         1       2
 35-39yrs      0         0         0         0         0         1       1
 40-49yrs      1         0         1         0         0         0       2
 50-54yrs      1         0         0         0         0         0       1
 Total         3         0         1         2         1         3       10

根据我的知识，唯一的方法是创建另一个视图并将它们一个一个分组。但我想知道是否有其他方法可以在不创建其他视图的情况下做到这一点？如果有人有其他好的建议，我希望学习它。非常感谢。

4

2 回答 2

1

MySQL 版本。在 SQL Server 和 Oracle 中都不起作用。SQL小提琴

select *, IT_Male + IT_Female + Finance_Male + Finance_Female + HR_Male + HR_Female as Total
from (
    select 
        ar.`range` as Age,
        count(Department = 'IT' and Gender = 'M' or null) as IT_Male,
        count(Department = 'IT' and Gender = 'F' or null) as IT_Female,
        count(Department = 'Finance' and Gender = 'M' or null) as Finance_Male,
        count(Department = 'Finance' and Gender = 'F' or null) as Finance_Female,
        count(Department = 'HR' and Gender = 'M' or null) as HR_Male,
        count(Department = 'HR' and Gender = 'F' or null) as HR_Female
    from 
        JOB_Details jd
        inner join
        age_range ar on jd.Age between ar.bottom and ar.top
    group by ar.`range`
    order by ar.bottom
) s
union
select 
    'Total',
    count(Department = 'IT' and Gender = 'M' or null),
    count(Department = 'IT' and Gender = 'F' or null),
    count(Department = 'Finance' and Gender = 'M' or null),
    count(Department = 'Finance' and Gender = 'F' or null),
    count(Department = 'HR' and Gender = 'M' or null),
    count(Department = 'HR' and Gender = 'F' or null),
    count(*)
from JOB_Details

没有外部表或视图的 Oracle 版本：SQL Fiddle

with age_range as (
    select 0 as "bottom", 29 as "top", '<30' as "range" from dual union
    select 30, 34, '30-34' from dual union
    select 35, 39, '35-59' from dual union
    select 40, 49, '40-49' from dual union
    select 50, 54, '50-54' from dual
)
select s.*, IT_Male + IT_Female + Finance_Male + Finance_Female + HR_Male + HR_Female as Total
from (
    select 
        ar."range" as Age,
        count(case when Department = 'IT' and Gender = 'M' then 1 end) as IT_Male,
        count(case when Department = 'IT' and Gender = 'F' then 1 end) as IT_Female,
        count(case when Department = 'Finance' and Gender = 'M' then 1 end) as Finance_Male,
        count(case when Department = 'Finance' and Gender = 'F' then 1 end) as Finance_Female,
        count(case when Department = 'HR' and Gender = 'M' then 1 end) as HR_Male,
        count(case when Department = 'HR' and Gender = 'F' then 1 end) as HR_Female
    from 
        JOB_Details jd
        inner join
        age_range ar on jd.Age between ar."bottom" and ar."top"
    group by ar."range", ar."bottom"
    order by ar."bottom"
) s
union
select 
    'Total',
    count(case when Department = 'IT' and Gender = 'M' then 1 end),
    count(case when Department = 'IT' and Gender = 'F' then 1 end),
    count(case when Department = 'Finance' and Gender = 'M' then 1 end),
    count(case when Department = 'Finance' and Gender = 'F' then 1 end),
    count(case when Department = 'HR' and Gender = 'M' then 1 end),
    count(case when Department = 'HR' and Gender = 'F' then 1 end),
    count(*)
from JOB_Details
于 2012-10-12T01:09:14.143 回答
0 
SELECT 
   CASE WHEN Age < 30 THEN '<30' 
        WHEN 30 <= Age AND Age < 34 THEN '30-34'
        ...
   END as Age,

   SUM(CASE WHEN Department = 'IT' AND Gender = 'M' THEN 1 ELSE 0) END AS IT_M,
   SUM(CASE WHEN Department = 'IT' AND Gender = 'F' THEN 1 ELSE 0) END AS IT_F,
   ...

FROM JOB_DETAILS

GROUP BY
   CASE WHEN Age < 30 THEN '<30y' 
        WHEN 30 <= Age AND Age < 34 THEN '30-34'
        ...
   END
于 2012-10-12T01:06:33.137 回答