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我要做的是找到前一天购买了一个Series X或Series A小部件的所有客户，只要这是他们第一次从中购买小部件。如果他们购买了多个符合条件的小部件Series X，那么我应该只获得它的记录。希望这是有道理的，所以这是数据

[customers]
c_id     cp_id
--------------
1        cp1
2        cp2
3        cp3
4        cp4
5        cp5
6        cp6
7        cp7
8        cp8
9        cp9
10       cp10

[widget_orders - c_id maps to c_id in customers]
c_id    w_sku   o_date
----------------------
1       w1      2012-10-10
2       w1      2012-10-10
2       w2      2012-10-10
3       w1      2012-10-10
3       w2      2012-10-10
4       w1      2012-10-10
4       w2      2012-10-10
5       w1      2012-10-10
5       w2      2012-10-10
6       w1      2012-10-10
6       w2      2012-10-10
7       w2      2012-10-10
8       w1      2012-10-10
9       w3      2012-10-10

[widgets - w_sku maps to w_sku in widget_orders]
w_sku   w_series
------------------
w1      Series A
w2      Series X
w3      Series C

[customer_data - c_id maps to c_id in customers]
cp_id   seriesA_fPurch  seriesX_fPurch
--------------------------------------
cp3     
cp4     2012-09-15
cp5                     2012-09-15
cp6     2012-09-15      2012-09-15
cp7                     2012-09-15  
cp8     2012-09-15

这是我想要返回的数据，忽略 () 中的描述

cp_id   series
--------------
cp1     Series A (bought series A and had NO prior purchase history)
cp2     Series X (bought both series, but X has rank - no purchase history)
cp3     Series X (bought both series, but X has rank - has purchase history recors albeit not for these)
cp4     Series X (bought both series, but X has rank - already had A history anyways)
cp5     Series A (bought both series, although X has rank they had previously bought series X)

以下人员未显示在结果中

cp6 - they had previously bought both series
cp7 - bought a series x, but had in the past
cp8 - bought a series a, but had in the past
cp9 - bought a widget in neither series
cp10 - didnt buy anything

希望所有这些都是有道理的，有人可以在这里帮助我！

所以总结一下逻辑，也许在这里更清楚地定义它是我将如何描述需要以类似步骤的方式发生的事情

1) Find all customers who have no matching records in the customer_data table
2) Find all customers who have a null value in either *purch column in the customer_data table
3) Combine these results together
4) Take the results and find the customers who made a purchase yesterday
5) Take the results and find the customers who purchased Series A or Series X
6) Take the results and do the following
    6a) If the purchase was Series A and they have a value for series A purch already drop them from results
    6b) If the purchase was Series X and they have a value for series X purch already drop them from results
7) Take the results and remove duplicate records based on the cp_id - Series X takes presedence over Series A
4

1 回答 1

2

我不确定我是否完全理解您的要求，但请尝试：

SELECT cp_id, w_series
FROM (
SELECT rank() over (partition BY wo."c_id" ORDER BY decode(w."w_series",'Series X',1,'Series A',2)) rank,
       wo."c_id" c_id,
       c."cp_id" cp_id,
       w."w_series" w_series
FROM widget_orders wo JOIN widgets w ON wo."w_sku"=w."w_sku"
  JOIN customers c on c."c_id"=wo."c_id"
LEFT OUTER JOIN customer_data cd ON c."cp_id" = cd."cp_id"
WHERE  w."w_series" IN ('Series A', 'Series X')
  AND  trunc(wo."o_date") = trunc(sysdate)-1
  AND ( (cd."seriesA_fPurch" IS NULL AND w."w_series"='Series A')
     OR (cd."seriesX_fPurch" IS NULL AND w."w_series"='Series X'))
  )
WHERE rank = 1

这是一个小提琴

说明：
根据阶梯式数字-
1) + 2) 在LEFT OUTER JOIN+cd."seriesA_fPurch" IS NULL条件+cd."seriesX_fPurch" IS NULL条件中完成，因为它也会找到那些没有记录的人并在其中放入空值。
3) 明显...
4)trunc(wo."o_date") = trunc(sysdate)-1条件
5) w."w_series" IN ('Series A', 'Series X')
6)(cd."seriesA_fPurch" IS NULL AND w."w_series"='Series A') OR (cd."seriesX_fPurch" IS NULL AND w."w_series"='Series X')条件
7) 通过对记录和WHERE rank = 1条件进行排名

于 2012-10-11T21:27:09.480 回答