0

我正在尝试加入这些陈述：

select min(len(Password)) as min, 
       max(len(Password)) as max, 
       avg(len(Password)) as avg 
FROM Customer.dbo.Password 

UNION ALL
select min(len(password2)) as min, 
       max(len(password2)) as max, 
       avg(len(password2)) as avg 
FROM website.dbo.password2

对这些：

SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'website' db FROM website.sys.all_columns as c INNER JOIN website.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U'

UNION
SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'Customer' db FROM Customer.sys.all_columns as c INNER JOIN Customer.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U'

它们没有共同的列。前两个 SELECT 语句生成密码长度的 min、max 和 avg 三列，后两个生成密码所在位置的 colName、tableName 和 db 名称。

纯粹出于视觉原因，我想在一个表中显示两个结果集，以获取与适当的 colName、tableName 和 db 相对应的 min、max、avg。

我试过这样做：

DECLARE @numberTable TABLE (link nvarchar(500), max int, min int, avg int)
INSERT INTO @numberTable

select 'link', min(len(Password)) as min, 
       max(len(Password)) as max, 
       avg(len(Password)) as avg 
FROM Customer.dbo.Password UNION ALL
select 'link', min(len(password2)) as min, 
       max(len(password2)) as max, 
       avg(len(password2)) as avg 
FROM website.dbo.password2

SELECT * FROM @numberTable ORDER BY max

DECLARE @myTable TABLE (link nvarchar(500), colName nvarchar(500), tableName   nvarchar(500), db nvarchar(500))
INSERT INTO @myTable

SELECT 'link', c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'website' db FROM website.sys.all_columns as c INNER JOIN website.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' UNION

SELECT 'link', c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'Customer' db FROM Customer.sys.all_columns as c INNER JOIN Customer.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' 

SELECT * FROM @myTable ORDER BY db

SELECT link
FROM @myTable
LEFT OUTER JOIN @numberTable
ON @myTable.link = @numberTable.link

不幸的是，这没有用。

我正在使用 Microsoft SQL Server 2008。

希望我所追求的有意义。

4

2 回答 2

1

您可以使用cross join连接两个不相关的表：

SELECT  c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName
,       o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName
,       'website' db 
,       pwd.[min]
,       pwd.[max]
,       pwd.[avg]
FROM    website.sys.all_columns as c 
INNER JOIN 
        website.sys.all_objects o 
ON      c.object_id = o.object_id 
CROSS JOIN
        (
        select min(len(Password)) as min, 
               max(len(Password)) as max, 
               avg(len(Password)) as avg 
        FROM   website.dbo.Password        
        ) as pwd
WHERE   c.name like '%password%' 
        AND type = 'U' 

UNION

SELECT  c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName
,       o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName
,       'Customer' db 
,       pwd.[min]
,       pwd.[max]
,       pwd.[avg]
FROM    Customer.sys.all_columns as c 
INNER JOIN 
        Customer.sys.all_objects o 
ON      c.object_id = o.object_id 
CROSS JOIN
        (
        select min(len(Password)) as min, 
               max(len(Password)) as max, 
               avg(len(Password)) as avg 
        FROM    Customer.dbo.Password        
        ) as pwd
WHERE   c.name like '%password%' 
        AND type = 'U'
于 2012-10-11T08:45:24.677 回答
0

创建他们确实有共同点的任意东西并加入他们

Select * 
from
(
select 
       1 as RowID,
       min(len(Password)) as min,  
       max(len(Password)) as max,  
       avg(len(Password)) as avg  
FROM Customer.dbo.Password  

UNION ALL 
select 
       2,
       min(len(password2)) as min,  
       max(len(password2)) as max,  
       avg(len(password2)) as avg  
FROM website.dbo.password2 
) t1
inner join
(


SELECT 1 as RowID, c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'website' db FROM website.sys.all_columns as c INNER JOIN website.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' 

UNION 
SELECT 2, c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'Customer' db FROM Customer.sys.all_columns as c INNER JOIN Customer.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' 
) t2
    on t1.rowID = t2.rowID
于 2012-10-11T08:48:18.247 回答