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我正在尝试使用此脚本创建数据库。但我在黑洞里。我不知道现在该怎么办。这是我的 MySQL 代码。请有人踢我。

如果我使用一个外键没问题，但我不知道如何使用更多。

EROOR 是：

#1005 - Can't create table 'ruda_dev_souteze2.results' (errno: 150)

查询是：

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';

CREATE SCHEMA IF NOT EXISTS `ruda_dev_souteze2` DEFAULT CHARACTER SET utf8 COLLATE utf8_czech_ci ;

USE `ruda_dev_souteze2` ;

-- -----------------------------------------------------
-- Table `ruda_dev_souteze2`.`contests`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`contests` (
  `id` BIGINT(20) NOT NULL AUTO_INCREMENT ,
  `name` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `date` DATE NOT NULL ,
  `public` TINYINT(1) NOT NULL ,
  PRIMARY KEY (`id`) )
ENGINE = InnoDB
AUTO_INCREMENT = 11
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_czech_ci;


-- -----------------------------------------------------
-- Table `ruda_dev_souteze2`.`people`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`people` (
  `contest_id` BIGINT(20) NOT NULL ,
  `number` INT(11) NOT NULL ,
  `category` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `fname` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `lname` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  PRIMARY KEY (`contest_id`, `number`) ,
  INDEX `id_idx` (`contest_id` ASC) ,
  CONSTRAINT `cidfp`
    FOREIGN KEY (`contest_id` )
    REFERENCES `ruda_dev_souteze2`.`contests` (`id` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_czech_ci;


-- -----------------------------------------------------
-- Table `ruda_dev_souteze2`.`subjects`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`subjects` (
  `contest_id` BIGINT(20) NOT NULL ,
  `number` INT(11) NOT NULL ,
  `name` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `direct` TINYINT(1) NOT NULL ,
  `type` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `subjectscol` VARCHAR(45) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NULL DEFAULT NULL ,
  PRIMARY KEY (`contest_id`, `number`) ,
  INDEX `id_idx` (`contest_id` ASC) ,
  CONSTRAINT `cidfs`
    FOREIGN KEY (`contest_id` )
    REFERENCES `ruda_dev_souteze2`.`contests` (`id` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_czech_ci;


-- -----------------------------------------------------
-- Table `ruda_dev_souteze2`.`results`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`results` (
  `contest_id` BIGINT(20) NOT NULL ,
  `subject_number` INT(11) NOT NULL ,
  `people_number` INT(11) NOT NULL ,
  `number_8c2` FLOAT(10,2) NULL DEFAULT NULL ,
  `time_time` TIME NULL DEFAULT NULL ,
  `time_frag` FLOAT(2,2) NULL DEFAULT NULL ,
  PRIMARY KEY (`contest_id`, `subject_number`, `people_number`) ,
  INDEX `cidfr_idx` (`contest_id` ASC) ,
  INDEX `snfr_idx` (`subject_number` ASC) ,
  INDEX `pnfr_idx` (`people_number` ASC) ,
  CONSTRAINT `cidfr`
    FOREIGN KEY (`contest_id` )
    REFERENCES `ruda_dev_souteze2`.`contests` (`id` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `snfr`
    FOREIGN KEY (`subject_number` )
    REFERENCES `ruda_dev_souteze2`.`subjects` (`number` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `pnfr`
    FOREIGN KEY (`people_number` )
    REFERENCES `ruda_dev_souteze2`.`people` (`number` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_czech_ci;


-- -----------------------------------------------------
-- Table `ruda_dev_souteze2`.`users`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`users` (
  `username` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `fullname` VARCHAR(255) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  `password` BINARY(40) NOT NULL ,
  `access` CHAR(1) CHARACTER SET 'utf8' COLLATE 'utf8_czech_ci' NOT NULL ,
  PRIMARY KEY (`username`) )
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_czech_ci;



SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;
4

2 回答 2

1

我想我明白你在问什么（如果没有，请澄清）。

在CREATE TABLE对表的查询results中，您尝试创建三个单独FOREIGN KEY的列，每个列都转到不同的表。查询中的问题是这三行：

INDEX `cidfr_idx` (`contest_id` ASC) ,
INDEX `snfr_idx` (`subject_number` ASC) ,
INDEX `pnfr_idx` (`people_number` ASC) ,

如果您更改INDEX为KEY它应该可以正常工作。此外，ASC这是默认设置 - 因此从技术上讲，您可以将其排除在外（但将其保留不会有任何伤害。

所以，在这个小更新之后，你CREATE TABLE的results表应该如下所示：

CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`results` (
  `contest_id` BIGINT(20) NOT NULL ,
  `subject_number` INT(11) NOT NULL ,
  `people_number` INT(11) NOT NULL ,
  `number_8c2` FLOAT(10,2) NULL DEFAULT NULL ,
  `time_time` TIME NULL DEFAULT NULL ,
  `time_frag` FLOAT(2,2) NULL DEFAULT NULL ,
  PRIMARY KEY (`contest_id`, `subject_number`, `people_number`) ,
  KEY `cidfr_idx` (`contest_id`) ,
  KEY `snfr_idx` (`subject_number`) ,
  KEY `pnfr_idx` (`people_number`) ,
  CONSTRAINT `cidfr`
    FOREIGN KEY (`contest_id` )
    REFERENCES `ruda_dev_souteze2`.`contests` (`id` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `snfr`
    FOREIGN KEY (`subject_number` )
    REFERENCES `ruda_dev_souteze2`.`subjects` (`number` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `pnfr`
    FOREIGN KEY (`people_number` )
    REFERENCES `ruda_dev_souteze2`.`people` (`number` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_czech_ci;

我使用更改在本地测试了完整的脚本，它运行良好 - 如果您有任何问题，请告诉我，我可以进一步调查。

于 2012-10-11T02:07:31.063 回答
1

引用的列是BIGINT：

CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`subjects` (
  `contest_id` BIGINT(20) NOT NULL ,                           --- BIGINT
 ...

而参考是INT：

CREATE  TABLE IF NOT EXISTS `ruda_dev_souteze2`.`results` (
  `contest_id` BIGINT(20) NOT NULL ,
  `subject_number` INT(11) NOT NULL ,                          --- INT
    ...
  CONSTRAINT `snfr`
    FOREIGN KEY (`subject_number` )
    REFERENCES `ruda_dev_souteze2`.`subjects` (`number` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,

它们应该具有相同的数据类型。

于 2012-10-12T06:16:01.283 回答