I'm trying to open a file and append data to it using ExtAudioFileWrite. Now, creating/initial writing(on creation)/converting works just fine, but unfortunately I can't seem to be able to open the file for writing afterwards. There is only one function that seems to open the file: ExAudioFileOpenURL
but only for reading. So, how can I write at the end of a file if I'm not able to open the file for writing?
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0
我可能错了,或者没有完全理解你的问题。但是,一旦您开始使用 ExtAudioFileWrite 写入文件,您可以通过再次调用 ExtAudioFileWrite 继续写入文件。我即将冒险在没有编译器的情况下进行编码,希望你能明白
例子:
....variables declaration and your logic.....
//1.Create File to write output
ExtAudioFileRef outputFile;
//+++++++ LOOP to append as many files as you want +++++++//
//2.Create file reference to files you want to merge
ExtAudioFileRef audioFileObject = 0;
//3.open the first file
ExtAudioFileOpenURL (firstFileURL, &audioFileObject);
//4.get file properties
AudioStreamBasicDescription AudioFileFormat = 0;
UInt64 numberOfPacketsToReadInCurrentFile = 0;
ExtAudioFileGetProperty(audioFileObject,
kExtAudioFileProperty_FileLengthFrames,
sizeof(numberOfPacketsToReadInCurrentFile),
&numberOfPacketsToReadInCurrentFile
);
ExtAudioFileGetProperty(audioFileObject,
kExtAudioFileProperty_FileDataFormat,
sizeof(AudioFileFormat),
&AudioFileFormat
);
//5.Set destination ASBD
ExtAudioFileSetProperty(audioFileObject,
kExtAudioFileProperty_ClientDataFormat,
sizeof (importFormat),
&importFormat
);
//6.Set/Create/Allocate Some Buffers
//use AudioFileFormat to setup your buffers accordingly
AudioBufferList theBufferList = 0 // bufferList setup (I dont remember that)
//7.Read the file into the buffer
ExtAudioFileRead(audioFileObject,&numberOfPacketsToReadInCurrentFile,theBufferList);
//8.Write the buffer to a File
ExtAudioFileWrite(outputFile, numberOfPacketsToReadInCurrentFile, theBufferList);
free(theBufferList);
//if you want to append more files go to point 2 with the next file URL
//+++++++CLOSE LOOP+++++++++//
//once you are done.. just dispose the file and clean up everything left
ExtAudioFileDispose(outputFile);
我猜这不会编译。但希望能帮助您了解这个想法。
于 2012-10-22T10:31:58.927 回答