python - 使用python从目录中的所有.txt文件中获取行

Question

我在一个目录中有一些 txt 文件，我需要从所有这些文件中获取最后 15 行。我怎么能用python做到这一点？

我选择了这段代码：

from os import listdir
from os.path import isfile, join

dir_path= './'
files = [ f for f in listdir(dir_path) if isfile(join(dir_path,f)) ]
out = []
for file in files:
    filedata = open(join(dir_path, file), "r").readlines()[-15:]
    out.append(filedata)
f = open(r'./fin.txt','w')
f.writelines(out)
f.close()

但我收到错误“TypeError：writelines() 参数必须是字符串序列”。我认为这是因为行中的俄罗斯字母。

Answer 1

import os
from collections import deque

for filename in os.listdir('/some/path'):
    # might want to put a check it's actually a file here...
    # (join it to a root path, or anything else....)
    # and sanity check it's text of a usable kind
    with open(filename) as fin:
        last_15 = deque(fin, 15)

deque将自动丢弃最旧的条目并将最大大小峰值为 15，因此这是仅保留“最后”“n”个项目的有效方法。

Answer 2

尝试这个：

from os import listdir
from os.path import isfile

for filepath in listdir("/path/to/folder")
    if isfile(filepath): # if need
        last_five_lines = open(filepath).readlines()[-15:]

# or, one line:

x = [open(f).readlines()[-15:] for f in listdir("/path/to/folder") if isfile(f)]

更新：

lastlines = []
for file in files:
    lastlines += open(join(dir_path, file), "r").readlines()[-15:]
with open('./fin.txt', 'w') as f:
    f.writelines(lastlines)

Answer 3

from os import listdir
from os.path import isfile, join

dir_path= '/usr/lib/something'
files = [ f for f in listdir(dir_path) if isfile(join(dir_path,f)) ]

for file in files:
    filedata = open(join(dir_path, file), "r").readlines()[-15:]
    #do something with the filedata

Answer 4

希望这可以帮助：

import os

current_dir = os.getcwd()
dir_objects = os.listdir(current_dir)
dict_of_last_15 = {}
for file in dir_objects:
    file_obj = open(file, 'rb')
    content = file_obj.readlines()
    last_15_lines = content[-15:]
    dict_of_last_15[file] = last_15_lines
    print "#############: %s" % file
    print dict_of_last_15[file]
    file_to_check.close()