0

我有一个按钮“提交”,我想在静态方法中创建“submit.performclick”,我试过但我不能,帮助我克服这个问题,还有一件事,在那个点击动作中,可能有任何非静态方法..但我想让按钮点击。

 new_btn.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            CallingDataBase("fm Btn","from button");
            ClearMemory();
        }
    });
public void CallingDataBase(String mobileNumber, String mobileMessage)
{
        us = mobileNumber;
        pa = mobileMessage;
        insertion(us,pa);
        CallingCustomAdapter();
}

//this static method was the first calling method.
  public static void updateMessageBox(String mobileNum12, String mobileMessa12,Context context)
//I get parameters for this method from another class.
{   

//      SMS smsClass = new SMS();    // SMS was my Class Name`
//      smsClass.function(context);
//       from here i want to call button action   


}
4

1 回答 1

0

您可以通过以下方式为静态方法提供对按钮的引用作为参数:

//this static method was the first calling method.
public static void updateMessageBox( Button button , String mobileNum12, String mobileMessa12,Context context)
//I get parameters for this method from another class.
{   

//      SMS smsClass = new SMS();    // SMS was my Class Name`
//      smsClass.function(context);
//       from here i want to call button action   
button.performClick();

}
于 2012-10-10T04:57:26.570 回答