-1

我使用 OAuthStarter Kit 来访问 LinkedIn API。我成功获得了权限的访问令牌。

rw_ns
r_basicprofile
r_fullprofile

可以获取个人资料详细信息以及仅共享评论以及共享 URL 或图像或描述等...我使用以下代码：

-(void)postUpdate
 {
   NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
   OAMutableURLRequest *request =
   [[OAMutableURLRequest alloc] initWithURL:url
                            consumer:[self getConsumer]
                               token:self.accesstoken
                            callback:nil
                   signatureProvider:nil];

   NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:

                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                     @"anyone",@"code",nil], @"visibility",
                    @"title goes here",@"title",
                    @"comment goes here", @"comment",
                    @"description goes here",@"description",
                     @"www.google.com",@"submitted-url",
                    @"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submitted-image-url",
                    nil];
   [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
   [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];

   NSString *updateString = [update JSONString];
   [request setHTTPBodyWithString:updateString];
    [request setHTTPMethod:@"POST"];

   OADataFetcher *fetcher = [[OADataFetcher alloc] init];
   [fetcher fetchDataWithRequest:request
                 delegate:self
        didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
          didFailSelector:@selector(postUpdateApiCallResult:didFail:)];

  }

但我收到如下响应错误：

 2012-10-09 18:27:29.906 SocialConnectTest[9460:19a03] data {
 "errorCode": 0,
 "message": "Invalid xml {Expected elements 'post-network-update@http://api.linkedin.com/v1 id@http://api.linkedin.com/v1 visibility@http://api.linkedin.com/v1 comment@http://api.linkedin.com/v1 attribution@http://api.linkedin.com/v1 content@http://api.linkedin.com/v1 private-message@http://api.linkedin.com/v1 share-target-reach@http://api.linkedin.com/v1' instead of 'submitted-url@http://api.linkedin.com/v1' here in element share@http://api.linkedin.com/v1}",
 "requestId": "W2G7WJDHOJ",
 "status": 400,
 "timestamp": 1349787449685
}

而且我不知道问题是什么。谁能帮我解决这个问题？

4

1 回答 1

3

我修好了它。问题出在帖子参数中

  1. 根据 Linked in api 的文档，如果我们在请求正文中使用 JSON，则 post 参数的键必须是驼峰式，而在 xml 中使用“-”分隔的键名。
  2. 共享参数，如submitUrl 、 subsubmittedImageUrl 、 description、title **等。必须是名为 **content 的键的值。

所以我修改了代码如下..

-(void)postUpdateHERE
{
  NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
  OAMutableURLRequest *request =
  [[OAMutableURLRequest alloc] initWithURL:url
                            consumer:[self getConsumer]
                               token:self.accesstoken
                            callback:nil
                   signatureProvider:nil];

  NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:

                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                     @"anyone",@"code",nil], @"visibility",

                    @"comment goes here", @"comment",
                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                    @"description goes here",@"description",
                    @"www.google.com",@"submittedUrl",
                      @"title goes here",@"title",
                    @"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submittedImageUrl",nil],@"content",
                    nil];
  [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
  [request setValue:@"application/xml" forHTTPHeaderField:@"Content-Type"];
  NSString *updateString = [update JSONString];
  [request setHTTPBodyWithString:updateString];
  [request setHTTPMethod:@"POST"];
  OADataFetcher *fetcher = [[OADataFetcher alloc] init];
  [fetcher fetchDataWithRequest:request
                 delegate:self
        didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
          didFailSelector:@selector(postUpdateApiCallResult:didFail:)];

}

现在代码对我有用..

于 2012-10-09T15:05:53.273 回答